This can be simplified to -10p = -150 p = -150/-10 p = 15
p=2L+2W p=2(150)+2(15) p=300+30 p=330
p = -12
To find the perimeter of a rectangle with lengths of 150 and 75, you use the formula for perimeter, which is ( P = 2 \times (length + width) ). Plugging in the values, ( P = 2 \times (150 + 75) = 2 \times 225 = 450 ). Therefore, the perimeter is 450 units.
P = 2L + 2WP/2 = L + WW = P/2 - LW = 150/2 - 45 = 75 - 45 = 30A = LW = (45)(30) = 1350 unit2
This can be simplified to -10p = -150 p = -150/-10 p = 15
P. Nazarov has written: 'Ot Murmanska do Urala'
155
(p+150) + q = 1000 p+q= 1000-150 =850 Value of q is 425 and value of p 425 plus 150 ie. 575
150 Psalms in the Bible
I am doing a quiz and some of them are very hard and that is where you come in. What is-- 150=P in the B
p=2L+2W p=2(150)+2(15) p=300+30 p=330
V. P. Vdovichenko has written: 'Ot detstva k vzroslosti'
15 Points in a Game of Football at Overtime.
What percent of 24 is 150, written as an equation: P * 24 = 150Solve for P = 150/24 = 6.25 which is 625%
p = -12
150 Psalms of David (in the Bible)