110 nickels and 40 dimes my little brother had the same problem
Helen has twice as many dimes as nickels and five more quarters than nickels the value of her coins is 4.75 how many dimes does she have?
Eighteen
there r 40 nikels
Let ( d ) represent the number of dimes John has. Then, the number of nickels is ( d + 4 ). The total value of the coins can be expressed as ( 0.10d + 0.05(d + 4) = 1.25 ). Solving this equation, we find that John has 6 dimes and 10 nickels.
it would have to be pennies, 60 quarters is more than $7, same with dimes so pennies is the only one left.
Helen has twice as many dimes as nickels and five more quarters than nickels the value of her coins is 4.75 how many dimes does she have?
Eighteen
4 Qs 12 Dimes 20 Nickles
7 nickels, 4 dimes, 3 quarters
there r 40 nikels
Oh, dude, let's break it down. So, if we let x be the number of dimes, then the number of nickels would be x + 70. Since there are 150 coins total, we can set up the equation x + (x + 70) = 150. Solving it, we find that there are 60 dimes and 130 nickels. Easy peasy, lemon squeezy!
Let ( d ) represent the number of dimes John has. Then, the number of nickels is ( d + 4 ). The total value of the coins can be expressed as ( 0.10d + 0.05(d + 4) = 1.25 ). Solving this equation, we find that John has 6 dimes and 10 nickels.
7 nickels, 4 dimes, and 3 quarters.
Sam has more money If they have the same number of coins, but different values, than the one that has a higher numerical value will have more money. Sal has nickels, so he can only increase his amount by 5 cents, whereas Sam has dimes, so he can increase his amount by 10 instead.
This question cannot be answered.Assume there is1 nickel. There must be 3 more than that in quarters - that makes4 quarters and there are13 dimes---- that adds up to18
it would have to be pennies, 60 quarters is more than $7, same with dimes so pennies is the only one left.
You only need to solve for the number of either nickels or dimes. You can subtract that number from 86 to find the other. Since dimes are worth more, let's solve for dimes; we'll use the variable "d". First, make a chart of what we know:# dimes = "d"; 0.10 each; total cents in dimes = 10d# nickels = 86 - d, 0.05 each; total cents in nickels = 5(86-d)Total number/value of coins: total number is 86; total value $6.90, or 690 centsNow set up the equation:10d + 5(86-d) = 69010d + (5 . 86) + (5 . - d) = 69010d + 430 - 5d = 6905d + 430 = 6905d + 430 - 430 = 690 - 4305d = 260(1/5)5d = 260 (1/5)d = 52If there are 52 dimes, there must be 34 nickels (86 - 52 = 34).Let's check our work:52 dimes = $5.2034 nickels = $1.70$5.20 + 1.70 = $6.90