Helen has twice as many dimes as nickels and five more quarters than nickels the value of her coins is 4.75 how many dimes does she have?
Eighteen
there r 40 nikels
it would have to be pennies, 60 quarters is more than $7, same with dimes so pennies is the only one left.
Jack would have 11 Nickles && 7 Dimes. Promise you thattt, (:
Helen has twice as many dimes as nickels and five more quarters than nickels the value of her coins is 4.75 how many dimes does she have?
Eighteen
4 Qs 12 Dimes 20 Nickles
there r 40 nikels
7 nickels, 4 dimes, 3 quarters
7 nickels, 4 dimes, and 3 quarters.
Sam has more money If they have the same number of coins, but different values, than the one that has a higher numerical value will have more money. Sal has nickels, so he can only increase his amount by 5 cents, whereas Sam has dimes, so he can increase his amount by 10 instead.
it would have to be pennies, 60 quarters is more than $7, same with dimes so pennies is the only one left.
If there are 150 nickles and dimes and 70 more are nickles than dimes how many of each are there?
This question cannot be answered.Assume there is1 nickel. There must be 3 more than that in quarters - that makes4 quarters and there are13 dimes---- that adds up to18
Jack would have 11 Nickles && 7 Dimes. Promise you thattt, (:
You only need to solve for the number of either nickels or dimes. You can subtract that number from 86 to find the other. Since dimes are worth more, let's solve for dimes; we'll use the variable "d". First, make a chart of what we know:# dimes = "d"; 0.10 each; total cents in dimes = 10d# nickels = 86 - d, 0.05 each; total cents in nickels = 5(86-d)Total number/value of coins: total number is 86; total value $6.90, or 690 centsNow set up the equation:10d + 5(86-d) = 69010d + (5 . 86) + (5 . - d) = 69010d + 430 - 5d = 6905d + 430 = 6905d + 430 - 430 = 690 - 4305d = 260(1/5)5d = 260 (1/5)d = 52If there are 52 dimes, there must be 34 nickels (86 - 52 = 34).Let's check our work:52 dimes = $5.2034 nickels = $1.70$5.20 + 1.70 = $6.90