135 goes into 256 1 time with a remainder of 121.
135
13.5
No. 135 is divisible by: 1, 3, 5, 9, 15, 27, 45, 135.
225=135*1+110 135=110*1+25 110=25*4+10 25=10*2+5 10=5*2+0 so, the HCF of 135 and225 is 5.
135 goes into 256 1 time with a remainder of 121.
256 + 1 = 257
10/270 + 15/270 + 27/270 = 52/270 = 26/135
136
135
13.5
25+10+10+10+1+1= 57
No. 135 is divisible by: 1, 3, 5, 9, 15, 27, 45, 135.
2048
256-5 = 1/2565 = 9.094947 x 10-13 approximately,
225=135*1+110 135=110*1+25 110=25*4+10 25=10*2+5 10=5*2+0 so, the HCF of 135 and225 is 5.
.135 = 0 + (1/10) + (3/100) + (5/1000)