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Q: 1 2 0 3 -1
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How many different equations can be made with the numbers 0123?

A huge number. 0 + 1 + 2 = 3 0 + 2 + 1 = 3 1 + 0 + 2 = 3 1 + 2 + 0 = 3 2 + 0 + 1 = 3 2 + 1 + 0 = 3 -0 + 1 + 2 = 3 -0 + 2 + 1 = 3 1 - 0 + 2 = 31 + 2 - 0 = 32 - 0 + 1 = 32 + 1 - 0 = 3 0 - 1 + 3 = 2 0 + 3 - 1 = 2 -1 + 0 + 3 = 2 -1 + 3 + 0 = 2 3 + 0 - 1 = 2 3 - 1 + 0 = 2 -0 - 1 + 3 = 2-0 + 3 - 1 = 2-1 - 0 + 3 = 2-1 + 3 - 0 = 23 - 0 - 1 = 23 - 1 - 0 = 2 0 - 2 + 3 = 1 0 + 3 - 2 = 1 -2 + 0 + 3 = 1 -2 + 3 + 0 = 1 3 + 0 - 2 = 1 3 - 2 + 0 = 1 -0 - 2 + 3 = 1-0 + 3 - 2 = 1-2 - 0 + 3 = 1-2 + 3 - 0 = 13 - 0 - 2 = 13 - 2 - 0 = 1 1 + 2 - 3 = 0 1 - 3 + 2 = 0 2 + 1 - 3 = 0 2 - 3 + 1 = 0 -3 + 1 + 2 = 0 -3 + 2 + 1 = 0 For each of these equations there is a counterpart in which all signs have been switched. For example 0 + 1 + 2 = 3 gives -0 - 1 - 2 = -3and so on. Now, all of the above equations has three numbers on the left and one on the right. Each can be converted to others with two numbers on each side. For example:the equation 0 + 1 + 2 = 3 gives rise to0 + 1 = 3 - 20 + 1 = -2 + 30 + 2 = 3 - 10 + 2 = -1 + 31 + 2 = 3 - 01 + 2 = -0 + 3-0 + 1 = 3 - 2-0 + 1 = -2 + 3-0 + 2 = 3 - 1-0 + 2 = -1 + 31 + 2 = 3 + 01 + 2 = +0 + 3 As you can see, the number of equations is huge!


How do you play the harmonica part of 'That's What Friends Are For' on a guitar?

E|----------------|-------0-1-0----|----------------|--------1-0-----|--| B|--0-1-----0-1--|--0-1--------1-|------0-1-------|------1----1---|--| G|0-------0------|0--------------2|0-------------0-|-----2-------2-|0-| D|----------------|-----------------|----------------|3--3------------|--| A|----------------|-----------------|----------------|-----------------|--| E|----------------|-----------------|----------------|-----------------|--| E|----3-1---------|-----------------0-|1---------------| B|--------1-------|-----------3-1-----|----------------| G|----------0-----|0-------0----------|----------------| D|------------2-3|----2-3------------|----------------| A|----------------|--------------------|----------------| E|----------------|--------------------|----------------| E|----------------|--------0-1-0----|----------------|-------1-0-----|--| B|--0-1-----0-1-|---0-1-------1--|------0-1-------|------1----1---|--| G|0-------0------|-0--------------2|0------------0-|-----2-------2-|0-| D|----------------|------------------|----------------|3--3-----------|--| A|----------------|------------------|----------------|----------------|--| E|----------------|------------------|----------------|----------------|--|


What is the difference between -5 -1 2 5 1 -2 - 4 -4 -5 -2 -1 0 0 1?

+4 +3 +3 -4 -3 -2 0 -1 +3 +1+1 0 +1


How many ways can you make 4 using only 3?

I was only able to get 13 but I think there can be more, this is what i got: 0+0+4=4 4+0+0=4 0+4+0=4 0+1+3=4 0+3+1=4 0+2+2=4 1+2+1=4 1+1+2=4 1+3+0=4 2+2+0=4 2+0+2=4 3+1+0=4 3+0+1=4


How do you play a c scale on guitar?

|------------------------------------------------0--1--3------E |---------------------------------------0--1--3---------------A |---------------------------------0--2------------------------D |------------------------0--2--3------------------------------G |---------------0--2--3---------------------------------------B |------0--1--3------------------------------------------------e


What are the integers between -5 and 3?

8


Calculate determinants of a nxn matrix in C programming?

from: http://local.wasp.uwa.edu.au/~pbourke/other/determinant/ /* Recursive definition of determinate using expansion by minors. */ double Determinant(double **a,int n) { int i,j,j1,j2; double det = 0; double **m = NULL; if (n < 1) { /* Error */ } else if (n j1) continue; m[i-1][j2] = a[i][j]; j2++; } } det += pow(-1.0,1.0+j1+1.0) * a[0][j1] * Determinant(m,n-1); for (i=0;i<n-1;i++) free(m[i]); free(m); } } return(det); } //New Answer By Shaikh SOHIAL Hussain form PAKISTAN #include<stdio.h> #include<conio.h> void main () { clrscr(); int a[10][10],row,i=0,j=0,result,w,x,y,z; printf("This Program made 4 solve matrix determintae\n"); scanf("%d",&row); while(i<row) {printf("\n"); for(j=0;j<row;j++) { printf("Enter the value of %d%d\n",i,j); scanf("%d",&a[i][j]); } i++; } i=0; while(i<row) { printf("\n"); j=0; while( j<row) {printf("%d",a[i][j]); printf(" ");printf(" "); j++;} i++; } if(row==2) { result=(a[0][0]*a[1][1])-(a[0][1]*a[1][0]); printf("The answer is\t %d",result); } else if(row==3) { result=(a[0][0]*((a[1][1]*a[2][2])-(a[1][2]*a[2][1]))) - (a[0][1]*((a[1][0]*a[2][2])-(a[1][2]*a[2][0]))) + (a[0][2]*((a[1][0]*a[2][1])-(a[1][1]*a[2][0]))); printf("\nThe answer is \t %d",result); } else if(row==4) { w=a[0][0]*(a[1][1]*(a[2][2]*a[3][3]-a[2][3]*a[3][2])-a[1][2]*(a[2][1]*a[3][3]-a[2][3]*a[3][1])+a[1][3]*(a[2][1]*a[3][2]-a[2][2]*a[3][1])); x=a[0][1]*(a[1][0]*(a[2][2]*a[3][3]-a[2][3]*a[3][2])-a[1][2]*(a[2][0]*a[3][3]-a[2][3]*a[3][0])+a[1][3]*(a[2][0]*a[3][2]-a[2][2]*a[3][0])); y=a[0][2]*(a[1][0]*(a[2][1]*a[3][3]-a[2][3]*a[3][1])-a[1][1]*(a[2][0]*a[3][3]-a[2][3]*a[3][0])+a[1][3]*(a[2][0]*a[3][1]-a[2][1]*a[3][0])); z=a[0][3]*(a[1][0]*(a[2][1]*a[3][2]-a[2][2]*a[3][1])-a[1][1]*(a[2][0]*a[3][2]-a[2][2]*a[3][0])+a[1][2]*(a[2][0]*a[3][1]-a[2][1]*a[3][0])); result=w-x+y-z; printf("\n The answer is \t %d", result); } else{ printf("Determinate Limit is 4*4 max\n"); getch(); }


What is the midpoint of segment -3 3 and 1 -3?

(xM, yM) = [(-3 + 1)/2, (3 + -3)/2] = (-2/2, 0/2) = (-1, 0)


What is the mean number of 0 1 5 3 3 3 0 2 2?

(0 + 1 + 5 + 3 + 3 + 3 + 0 + 2 + 2) / 9 = 2.1 recurring (that is, 2.1111...)


What are the notes to can can violin?

d-0(2) d-0(2) d-1 d-3 d-2 d-1 a-0(2) a-0(2) a-0 a-1 d-2 d-3 d-1(2) d-1(2) d-1 d-3 d-2 d-1 d-0 a-3 a-2 a-1 a-0 d-3 d-2 d-1 d-0(2) d-0(2) d-1 d-3 d-2 d-1 a-0(2) a-0(2) a-0 a-1 d-2 d-3 d-1(2) d-1(2) d-1 d-3 d-2 d-0 a-0 d-1 d-2 d-0 a-3(2) (2)=2 beats [half note] the rest are 1 beat [quarter note] d= the string on the violin (g,d,a,e) -0=how many fingers you put on that string hope this helps!!!!!! >_< hehe...... =P


Jose is making a snack pack he has a bag of raisin nuts and pretzel each snack pack has 3 baghow many pack can he make?

10 different combinations can be made. Raisins Peanuts Pretzels 3 0 0 2 1 1 2 0 1 1 2 0 1 0 2 1 1 1 0 0 3 0 3 0 0 1 2 0 2 1


First six triangula numbers?

1 (0+1) 3 (0+1+2) 6 (0+1+2+3) 10 (0+1+2+3+4) 15 (0+1+2+3+4+5) 21 (0+1+2+3+4+5+6) Notice these are the numbers you can arrange into equalateral triangles.