311311122110
41 t(n) = (9n4 -110n3 + 477n2 -844n + 480)/12
16' then 25 and then 36 et.seq. The clue is 0,1,4,9,16,25,36, ... = 0^(2) , 1(2) , 2^(2), 3^(2) , 4^(2) , 5^(2) , 6^(2), ... n^(2) ...
The next term is -2.
The number that comes after 9100 is 9101. In the base-10 number system, each digit can range from 0 to 9 before incrementing to the next place value. Therefore, when we increment the last digit of 9100 by 1, it becomes 9101.
The number 0 and the next is 2.
The next number is 0
The next number in the sequence is 48.
12
4
132
311311122110
41 t(n) = (9n4 -110n3 + 477n2 -844n + 480)/12
16' then 25 and then 36 et.seq. The clue is 0,1,4,9,16,25,36, ... = 0^(2) , 1(2) , 2^(2), 3^(2) , 4^(2) , 5^(2) , 6^(2), ... n^(2) ...
This series is of the function f(x) = x2+1, starting with x=0.The next number in the series is 26. The number after that is 37.
There are infinitely many different polynomials of degree 8 that will fit all the numbers of the above sequence. Each will generate a different number as the next one in the sequence.
The next whole number after 1 is 2. However, the decimal after 1 can be an infinite chain of 0's, with a 1 at the end.