Q: 1 3 8 19 42

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1/3(8+19)=9

bro hi i will make it perfectly clearits logic is that multiply 1*2 +1=3, multiply 3*2=6add its result 6 into double of 8 i.e 16 and than ad into next two so 1*2+1=3,3*2=6,6+16=22+19=41+42=83 as it series of multiplication series no 3 every number is getting double

Using correct order of operations, 8*3+2=26.

3/12 =? 2/83/12 = 1/42/8 = 1/4So that 3/12 and 2/8 are equivalent fractions.

One solution is, 31 + (2 x 4) = 31 + 8 = 39 Another is, 42 - (1 x 3) = 42 - 3 = 39

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(1*2)+1=3 (3*2)+2=8 (8*2)+3=19 (19*2)+4=42 (42*2)+5=89 (89*2)+6=184 Basically the number times two and then add the the number it is in the sequence...i.e. 1 is the first number so add one, 3 is the second number so add two, etc.

1-(2)3-(5)8-(11)19-(23)42-(?)? 0*2=1 = 1 1*2=2 + 1 = 3 2*2+1 = 5 + preceding number = 8 5*2+1 = 11 + preceding number = 19 11*2+1 = 23 + preceding number = 42 23*2+1 = 47 + preceding number = 89 so I think the answer is 89.

Factors of 42 are 1, 2, 3, 6, 7, 14, 21, and 42

1/3(8+19)=9

bro hi i will make it perfectly clearits logic is that multiply 1*2 +1=3, multiply 3*2=6add its result 6 into double of 8 i.e 16 and than ad into next two so 1*2+1=3,3*2=6,6+16=22+19=41+42=83 as it series of multiplication series no 3 every number is getting double

8 + 42 * 3 = 8 + 16*3 = 8 + 48 = 568 + 42 * 3 = 8 + 16*3 = 8 + 48 = 568 + 42 * 3 = 8 + 16*3 = 8 + 48 = 568 + 42 * 3 = 8 + 16*3 = 8 + 48 = 56

1/2 x 19/4 = 19/8

Roughly 42%

42 has 8 factors: 1 2 3 6 7 14 21 42.

42/112 = 3/8

The factors of 24 are 1, 2, 3, 4, 6, 8, 12, and 24 The factors of 42 are 1, 2, 3, 6, 7, 14, 21, and 42

1, 2, 4, 8, 16 1, 2, 3, 6, 7, 14, 21, 42