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What is the answer to 1 divided by 2 times the square root of 2?
wow u cant figure out awnser relly the At first you will multiply the, (1 divided by 2 square root of 2) by (2square root of 2 divided by 2 square root of 2) because 2 square root of 2 is irrational. so the answer is square root of 2 over 4.
Square root of 12 over the square root of 4?
2 root 3 over 2, so square root of 3
What is the square root of x over 20 equals 1 over 2?
If it's just the square root of x, and that is over 20, you're looking for x=100. Here's why: 1/2 is one half. What number is 1/2 of 20? 10, right? What number has a square root that equals 10? 100! So~ the square root of 100 is 10. 10 out of 20 is equal to 1 out of 2.
What is the square root of 15 over square root of 30?
√15/√30 = √(15/30) = √(1/2)
What is the square root of ten over the square root of forty?
Oh, what a happy little question! When you have the square root of ten over the square root of forty, you can simplify it by dividing the square roots. So, the answer is the square root of ten over the square root of forty simplifies to one over the square root of four, which simplifies further to one over two. Just a little math magic to brighten your day!
What is the square root of 1 over 4?
the square root of (1/4) is 1/2
Square root of one half?
Square root of 1/2 = (1)/(square root of 2) = 1/1.4142 = 0.7071 Also Square root of 1/2 = Square root of 0.5 = 0.7071
What is the square root of 4 over 9?
The square root of the fraction 4/9 is either 2/3 or -2/3
Square root of 5 over 20?
1/2.
What is 1 divided by 1 plus the square root of 3?
root 3 - 1 all over 2
Is the square root of 4 rational and why?
yes its a rational number because the square root of 4 is 2 and 2 can be put over 1
What is sin 45?
one over the square root of 2 or 0.850903525
Find the two numbers whose product is 1 and whose sum is 1?
x + y = 1xy = 1y = 1 - xx(1 - x) = 1x - x^2 = 1-x^2 + x - 1 = 0 or multiplying all terms by -1;(-x^2)(-1) + (x)(-1) - (1)(-1) = 0x^2 - x + 1 = 0The roots are complex numbers. Use the quadratic formula and find them:a = 1, b = -1, and c = 1x = [-b + square root of (b^2 - (4)(a)(c)]/2a orx = [-b - square root of (b^2 - (4)(a)(c)]/2aSox = [-(-1) + square root of ((-1)^2 - (4)(1)(1)]/2(1)x = [1 + square root of (1 - 4]/2x = [1 + square root of (- 3)]/2 orx = [1 + square root of (-1 )(3)]/2; substitute (-1) = i^2;x = [1 + square root of (i^2 )(3)]/2x = [1 + (square root of 3)i]/2x = 1/2 + [i(square root of 3]/2 andx = 1/2 - [i(square root of 3)]/2Since we have two values for x, we will find also two values for yy = 1 - xy = 1 - [1/2 + (i(square root of 3))/2]y = 1 - 1/2 - [i(square root of 3)]/2y = 1/2 - [i(square root of 3)]/2 andy = 1 - [1/2 - (i(square root of 3))/2)]y = 1 - 1/2 + [i(square root of 3))/2]y = 1/2 + [i(square root of 3)]/2Thus, these numbers are:1. x = 1/2 + [i(square root of 3)]/2 and y = 1/2 - [i(square root of 3)]/22. x = 1/2 - [i(square root of 3)]/2 and y = 1/2 + [i(square root of 3)]/2Let's check this:x + y = 11/2 + [i(square root of 3)]/2 +1/2 - [i(square root of 3)]/2 = 1/2 + 1/2 = 1xy = 1[1/2 + [i(square root of 3)]/2] [1/2 - [i(square root of 3)]/2]= (1/2)(1/2) -(1/2)[i(square root of 3)]/2] + [i(square root of 3)]/2](1/2) - [i(square root of 3)]/2] [i(square root of 3)]/2]= 1/4 - [i(square root of 3)]/4 + [i(square root of 3)]/4 - (3i^2)/4; substitute ( i^2)=-1:= 1/4 - [(3)(-1)]/4= 1/4 + 3/4= 4/4=1In the same way we check and two other values of x and y.
Square root 14 divide into square root 7?
2
What is One over the square root of fifty?
1/ square root of 50 = 1/(5*√2), which when rationalizing the denominator becomes (√2) / 10, and as a decimal is .1414213562...
How do you find the square root of a quarter?
a quarter is 1/4 and square root of 1/4 is square root (1/4)=square root of 1 divided by square root of 4 which is 1 divided by 2. So the answer is 1/2
How can you solve the equation x2 plus 3i equals 0?
x2+3i=0 so x2=-3i x=square root of (-3i)=square root (-3)square root (i) =i(square root(3)([1/(square root (2)](1+i) and i(square root(3)([-1/(square root (2)](1+i) You can multiply through by i if you want, but I left it since it shows you where the answer came from. Note: The square root of i is 1/square root 2(1+i) and -1/square root of 2 (1+i) to see this, try and square them!
