The product is 140
28*5 = 140
To express (2^{-5} \times 28) as an exponential expression, we can first rewrite 28 in terms of base 2. Since (28 = 4 \times 7 = 2^2 \times 7), we can substitute this into the expression: [ 2^{-5} \times 28 = 2^{-5} \times (2^2 \times 7) = 2^{-5 + 2} \times 7 = 2^{-3} \times 7. ] Thus, the exponential expression is (2^{-3} \times 7).
5.6
5 times with a remainder of 3
140
28*5 = 140
28 can go into 140 a total of 5 times. This is because 28 multiplied by 5 equals 140. When you divide 140 by 28, the result is 5, indicating that 28 can fit into 140 exactly 5 times without any remainder.
5 times.
To express (2^{-5} \times 28) as an exponential expression, we can first rewrite 28 in terms of base 2. Since (28 = 4 \times 7 = 2^2 \times 7), we can substitute this into the expression: [ 2^{-5} \times 28 = 2^{-5} \times (2^2 \times 7) = 2^{-5 + 2} \times 7 = 2^{-3} \times 7. ] Thus, the exponential expression is (2^{-3} \times 7).
5.6
5 times with a remainder of 3
5 remainder 3.
28 times.
5 3/5
5 goes into 140 28 times.
140
Yes, 140 divided by 5 equals 28.