Days in February in a Leap Year
You've given the answer yourself. d=6 and f=3.
If: df+10f = 3 Then: f(d+10) = 3 And: d = 3/f -10
W = F x d W = Work F = Force d = Distance
-6 plus 2f plus 3f equals 29 -6 + 2f + 3f = 29 -6 + 5f = 29 5f = 35 f = 7
29 Days in February in a Leap Year.
It really should read "29 D in F in a LY" which is "29 Days in February in a Leap Year".The Mensa puzzles are good fun !
29 Days in February in a Leap Year
It is the 29 daysnin february in leap year.
Days in February in a Leap Year
What does a F and a D- queal out as
You've given the answer yourself. d=6 and f=3.
What does a F and a D- queal out as
If: df+10f = 3 Then: f(d+10) = 3 And: d = 3/f -10
29 degrees Fahrenheit = (-1.67) degrees Celsius[°C] = ([°F] − 32) × 5⁄9
29 days in february in a leap year.
a d = fDivide each side of the equation by 'd' :a = f/d