3 -4q = 10q + 10 3 - 10 = 10q + 4q -7 = 14q q = -1/2
9q - 14 + 3q - 8 = 7 So 9q + 3q = 7 + 14 + 8 ie 12q = 29 so q = 29/12 = 2.41666..
7 + 5 + 4 ÷ 2 + 7 = 21
5 + 2 + 3 + 7 + (21/7) = 20
2 + 12 + 7 = 21
3 -4q = 10q + 10 3 - 10 = 10q + 4q -7 = 14q q = -1/2
2(2q+7)(3q-2)
9q - 14 + 3q - 8 = 7 So 9q + 3q = 7 + 14 + 8 ie 12q = 29 so q = 29/12 = 2.41666..
-21q
7p + 2q = 46 . . . . (A) 5p + 3q = 36 . . . . (B) 3*(A): 21p + 6q = 138 2*(B): 10p + 6q = 72 Subtracting gives 11p = 66 so that p = 6 Substitute for p in (A): 7*6 + 2q = 46 or 42 + 2q = 46 which gives 2q = 4 so that q = 2 Solution: (p, q) = (6,2)
7 + 5 + 4 ÷ 2 + 7 = 21
5 + 2 + 3 + 7 + (21/7) = 20
It is: 12+7+2 = 21
-2 + (-6) + 7 = -1
-16 + -2 + 7 = -11
2 + 12 + 7 = 21
Commutative property of addition. :)