0+0+2=2 2 divided by 3 = 2/3
6x2-4x2+3 = 0 2x2 + 3 = 0 2x2 = -3 x2 = -3 / 2 this equation has imaginary roots x = +sqaureroot (3/2)i , -sqaureroot (3/2)i where i = complex variable
three 2 - 2 = 0 0 x 3 = 0 0 + 3 = 3
Factor it. y(4y - 1)(3y - 2) = 0 y = 0, 1/4, 2/3
43
9 is.
0+0+2=2 2 divided by 3 = 2/3
6x2-4x2+3 = 0 2x2 + 3 = 0 2x2 = -3 x2 = -3 / 2 this equation has imaginary roots x = +sqaureroot (3/2)i , -sqaureroot (3/2)i where i = complex variable
It is: 3^2 plus 2^3 = 17 meaning 9 plus 8 = 17
three 2 - 2 = 0 0 x 3 = 0 0 + 3 = 3
7x2-10x+3=0 (7x-3)(x-1)=0
the answer to 2+3+9+9+0=23 that is the professional way sio HA!!!!
Factor it. y(4y - 1)(3y - 2) = 0 y = 0, 1/4, 2/3
43
3,376
4*7*5+7^2-3*0+15 = 140+49-0+15 = 204
It is 0.