t > 3
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To solve the inequality 2t + 1 > 7, we need to isolate the variable t. First, subtract 1 from both sides which gives 2t > 6. Then, divide both sides by 2 to get t > 3. Therefore, t must be greater than 3 for the inequality to hold true.
12(t+6)+8=4(2t-1)+2t 12t+72+8=8t-4+2t 12t-2t-8t=-72-8-4 2t=-84 2t/2=84/2 t=42
3t - 1
2t^2+5t-3=0 (2t-1)(t+3)=0 2t-1=0 and t+3=0 t=.5 and t=-3
6t2+17t+7 = (3t+7)(2t+1) when factored
bcoz one has 3 digits o,n,e and 1 is single so 3+1>2 , thts why 1 plus one is greater than 2