one solution
write down the 2 equations
eq 1: 2x + y = 5
eq 2: 2y + x = 4
get a value for x from eq 2
x = 4 - 2y
substitute 4 - 2y for x in eq 1
2(4 - 2y) + y = 5
8 - 4y +y = 5
-3y = -3
y=1
substitute 1 for y in eq 2
2(1) + x = 4
2 + x = 4
x = 4-2
x = 2
parallel
-2x + 2y = 4 is equivalent to twice -2 + y = 2 which is the equation of a straight line.
2y = 4x + 4y = 2x + 2
k
(-2, 4)
(4, -1)
If: 12 = 2y+x then y = -1/2x+6 So: y = 2x+4 and y = -1/2x+6 which means that they are perpendicular lines
x = 2y = 4
4x + 2y = -8 → 2y = -4x - 8 → y = -2x - 4
-2X + 2Y = 4 2Y = 2X + 4 Y = X +2 by inspection, 2 but, you could also 0 out X in original equation -2(0) + 2Y = 4 2Y = 4 Y = 2
They are straight lines.
1 solution