Try the discriminant.
b^2 - 4ac
(-3)^2 - 4(2)(16)
9 - 128 < 0
so, no real roots here
9x squared plus 16 = 0 factored is plus and minus 4/3 i.
(b-4) squared
16
Two plus 3 minus 2 times 1 squared plus 4 times 16 squared minus 4 times 2 is equal to 1,019.
6
{-1,7}
9x squared plus 16 = 0 factored is plus and minus 4/3 i.
x^(2) - 10x + 16 = 0 Factors of '16', which are, 1,2,4,8,16. Select two numbers from this list that add/subtract to '10' . They are '2' and '8'. Setting up brackets ( x 2)(x 8) Since '16' is positive(+), then both signs must be the same. Since '10x' is negative (-) , then both signs are negative. Hence (x - 2)(x - 8 ) = 0 When x - 2 = 0 x = 2 & when x - 8 = 0 x = 8 So the two answers are ,2, & ,8, .
9x squared plus 16 = 0 factored is plus and minus 4/3 i.
(b-4) squared
16
Two plus 3 minus 2 times 1 squared plus 4 times 16 squared minus 4 times 2 is equal to 1,019.
x-8
16
2 squared plus 2 squared equals 16 because 2 squared is 4 times 4 equals 16. Math: 4x4=16 so your answer is 16 :)!
the answer of √8x+16-3x=0 is x= 0.447213595 = +/- 0.447(to 3 decimal places) if I'm not mistaken
6