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To convert the mixed numbers 3 12 and 4 38 into improper fractions, we first transform them: 3 12 becomes 3 + 12/12 = 3 + 1 = 4, so it's 4/1, and 4 38 becomes 4 + 38/38 = 4 + 1 = 5, so it's 5/1. The increase from 3 12 to 4 38 is from 4 to 5, which is an increase of 1. Thus, the increase is 1 whole unit.
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What is one fourth plus one third plus one half plus two thirds plus three fourths plus two thirds?
1/4 = 3/12 1/3 = 4/12 1/2 = 6/12 2/3 = 8/12 3/4 = 9/12 2/3 = 8/12 Setting it as a common denominator you can now add the top numbers and then simplify your answer. 3 + 4 + 6 + 8 + 9 + 8 = 38. 38 divided by 12 is your answer. (3 and 1/6th)
What is the rule 2 3 5 8 12 17 23 30 38?
+1, +2, +3, +4, +5, +6, +7, +8
What are the factor pairs of 38 and 48?
38 = 1*38, 2*1948 = 1*48, 2*24, 3*16, 4*12, 6*8
What is the next number in series 4 8 15 25 38?
n=number of term (ie 4 has n=1, 8 has n=2) t=value or term number 'n' (n=3 has t=15) Easy way: 4 --> 8 =+4 8 --> 15 = +7 15 --> 25 =+10 25 --> 38 = +13 Note: increases are also increasing by 3 Note: next increase should be +16 38+16=54 4 --> 8 = +4 4 --> 15 =+11 4 --> 25 =+21 4 --> 38 =+34 +4 = 4+0 +11= (4+0)[previous increase]+(4+0+3) [initial increase plus 3] +21= ((4+0)+(4+0+3))[previous increase]+((4+0+3)+3)[initial increase plus 3 again] +34= ((4+0)+(4+0+3))+((4+0+3)+3)[previous increase]+4+0+3+3+3 +4= 4*1+3*0 +11 = 4*2+3*1 +21 = 4*3+3*3 +34 = 4*4+3*6 Note: 0,1,3,6 are the sums of an arithmetic series that increases by 1 and starts at 0 (ie. 0=0, 1=0+1, 3=0+1+2) S=(n/2)(2n(initial)+(n-1)d) where n = term number where n(initial) = n where t=1 where d = increase in series S=(n/2)(2*0+(n-1)*1) S=(n/2)(n-1) Therefore additions: 4n+3*(n/2)(n-1) So, for the first increase (ie 4 --> 8). The increase = 4*1+3*0.5*0=4 1st increase = 4*1+3*0.5*0=4 2nd increase = 4*2+3*1*1=11 3rd increase = 4*3+3*1.5*2= 21 Note if you add 4(the first term of the initial series you get the right answers but shifted one term: ie: with: 4+4n+3*(n/2)(n-1) = 4(n+1)+3*(n/2)(n-1) t1=8 t2=15 t3=25 t4=38 Merely shift the n values to correct (ie. n --> n-1, n-1 --> n-2 etc.): t = 4n+3((n-1)/2)(n-2) t6= 4*6+3*2.5*4=24+30=54
What is three one sixths minus one one half minus three fourth?
31/6 - 11/2 - 3/4 = 19/6 - 3/2 - 3/4 = 38/12 - 18/12 - 9/12 = 11/12
What are the factors of 38 and 12?
1, 2, 3, 4, 6, 12 1, 2, 19, 38
What are all the factors of 12 and 38?
1, 2, 3, 4, 6, 12 1, 2, 19, 38
How do you get 38 out of 3427 using plus -x?
(3*4 + 7)*2 = (12+7)*2 = 19*2 = 38
What is one fourth plus one third plus one half plus two thirds plus three fourths plus two thirds?
1/4 = 3/12 1/3 = 4/12 1/2 = 6/12 2/3 = 8/12 3/4 = 9/12 2/3 = 8/12 Setting it as a common denominator you can now add the top numbers and then simplify your answer. 3 + 4 + 6 + 8 + 9 + 8 = 38. 38 divided by 12 is your answer. (3 and 1/6th)
How do you make 38 using 1 2 3 4?
2*(1 + 3!) + 4! = 2*(1 + 6) + 24 = 2*7 + 24 = 14 + 24 = 38
What is the rule 2 3 5 8 12 17 23 30 38?
+1, +2, +3, +4, +5, +6, +7, +8
What are the factor pairs of 38 and 48?
38 = 1*38, 2*1948 = 1*48, 2*24, 3*16, 4*12, 6*8
What are the factors of 24 and 38?
The factors of 24 are: 1, 2, 3, 4, 6, 8, 12, 24 The factors of 38 are: 1, 2, 19, 38
What are the factors of 38 and 36?
1, 2, 19, 38 1, 2, 3, 4, 6, 9, 12, 18, 36
What is the next number in series 4 8 15 25 38?
n=number of term (ie 4 has n=1, 8 has n=2) t=value or term number 'n' (n=3 has t=15) Easy way: 4 --> 8 =+4 8 --> 15 = +7 15 --> 25 =+10 25 --> 38 = +13 Note: increases are also increasing by 3 Note: next increase should be +16 38+16=54 4 --> 8 = +4 4 --> 15 =+11 4 --> 25 =+21 4 --> 38 =+34 +4 = 4+0 +11= (4+0)[previous increase]+(4+0+3) [initial increase plus 3] +21= ((4+0)+(4+0+3))[previous increase]+((4+0+3)+3)[initial increase plus 3 again] +34= ((4+0)+(4+0+3))+((4+0+3)+3)[previous increase]+4+0+3+3+3 +4= 4*1+3*0 +11 = 4*2+3*1 +21 = 4*3+3*3 +34 = 4*4+3*6 Note: 0,1,3,6 are the sums of an arithmetic series that increases by 1 and starts at 0 (ie. 0=0, 1=0+1, 3=0+1+2) S=(n/2)(2n(initial)+(n-1)d) where n = term number where n(initial) = n where t=1 where d = increase in series S=(n/2)(2*0+(n-1)*1) S=(n/2)(n-1) Therefore additions: 4n+3*(n/2)(n-1) So, for the first increase (ie 4 --> 8). The increase = 4*1+3*0.5*0=4 1st increase = 4*1+3*0.5*0=4 2nd increase = 4*2+3*1*1=11 3rd increase = 4*3+3*1.5*2= 21 Note if you add 4(the first term of the initial series you get the right answers but shifted one term: ie: with: 4+4n+3*(n/2)(n-1) = 4(n+1)+3*(n/2)(n-1) t1=8 t2=15 t3=25 t4=38 Merely shift the n values to correct (ie. n --> n-1, n-1 --> n-2 etc.): t = 4n+3((n-1)/2)(n-2) t6= 4*6+3*2.5*4=24+30=54
What number best complete this sequence 2 6 3 8 6 12?
It would seem to be 11. ------------------------------------- Here are a couple of ways to justify the answer "11": #1: 2 -> 6 is an increase of 4. 6 -> 3 is a decrease of 3. 3 -> 8 is an increase of 5. 8 -> 6 is a decrease of 2. 6 -> 12 is an increase of 6. 12 -> 11 is a decrease of 1. #2: 2 -> 3 is an (odd) increase of 1. 6 -> 8 is an (even) increase of 2. 3 -> 6 is an (odd) increase of 3. 8 -> 12 is an (even) increase of 4. 6 -> 11 is an (odd) increase of 5.
What are the factors of 12 38 40 and 94?
The factors of 12 are: 1, 2, 3, 4, 6, 12 The factors of 38 are: 1, 2, 19, 38 The factors of 40 are: 1, 2, 4, 5, 8, 10, 20, 40 The factors of 94 are: 1, 2, 47, 94
