3*6*2+5+5+54=100
3x3x5-6+2+54+5=100
(3*5)+(6 to the power of 2)+54-5
3(5-6)+2(54)-5 3TIMES -1 =-3 +108-5 105-5=100 PROBLEM SOLVED mike mount
As a product of its prime factors: 2*3*3*3 = 54
3*6*2+5+5+54=100
3x3x5-6+2+54+5=100
(3*5)+(6 to the power of 2)+54-5
3(5-6)+2(54)-5 3TIMES -1 =-3 +108-5 105-5=100 PROBLEM SOLVED mike mount
3+5=8 8+6=14 14+2=16 16+5=21 21+54=75 it doesn't equal 100.
[3 x (5 - 6)] + (2 x 54) - 5 = -3 + 108 -5 = 100 Note : The first step could be [3 / (5 - 6)] as this also produces the result -3.
As a product of its prime factors: 2*3*3*3 = 54
(2 x 54) + 3 - 5 - 6 = 108 + 3 - 11 = 100
(54, -1) (27, -2) (18, -3) (9, -6) (6, -9) (3, -18) (2, -27) (1, -54)
54 = 2 x 3³ So, if a and b are integers, a=2 and b=3
Factorization of 54: 1 x 54 2 x 27 3 x 18 6 x 9
3/2 ?