Let's say that s is the total number of students, b is the number of boys, g is the total number of girls, n is the number of non-blonde girls, and e is the number if blonde girls. We know that s = b + g, b = g, g = n + e, e = g/3, and n = 10. Substituting for b in the first equation gives us s = g + g = 2g Then we substitute for n and e in the third equation and solve for g: g = g/3 + 10 g - g/3 = 10 g - (1/3)g = 10 (2/3)g = 10 g = 10 x (3/2) = 15 Finally, solve for s: s = 2g = 2 x 15 = 30
goldilocks and the 3 bears
3 wishes from the genie in the bottle
B/G = 4/3 so 3B = 4G B+G = 21 Multiply by 3: 3B+3G = 63 But 3B = 4G so 4G+3G = 63 ie 7G = 63 so that G = 9 So B+G=21 means B = 12 3 more boys so B' = 12+3 = 15 1 more girl so G' = 9+1 = 10 So new ratio = B'/G' = 15/10 = 3/2 or 3 to 2
This is a Ditloid 147 maximum break in a game of snooker.
The B. G. was born on September 3, 1980.
3 b with g is 3 bears with goldilocks
Let's say that s is the total number of students, b is the number of boys, g is the total number of girls, n is the number of non-blonde girls, and e is the number if blonde girls. We know that s = b + g, b = g, g = n + e, e = g/3, and n = 10. Substituting for b in the first equation gives us s = g + g = 2g Then we substitute for n and e in the third equation and solve for g: g = g/3 + 10 g - g/3 = 10 g - (1/3)g = 10 (2/3)g = 10 g = 10 x (3/2) = 15 Finally, solve for s: s = 2g = 2 x 15 = 30
E g e g e e g a b a g a / e g e g e e g a b a g a / e g e g e e g a b a g a e a b a / b a g / g g f f /f g a g g / b a g / g g f f / g a b g g g a b c2 / b b b g b g b b g b b b / g b g b b g / b b b g b g b g /c2 a g g g /c2 a g g g ................
3 strikes you're out at the old ball game
Suppose there are B boys and G girls. Then Sophie has B brothers and (G-1) sisters - remember to leave Sophie out. So B = (G-1) + 5 ie B = G + 4 Also Joe has (B-1) brothers and G sisters So (B-1) = 2*G Substituting the value of B from Sophie's equation into this one gives (S+4 - 1) = 2*G ie G+3 = 2*G Subtract G from both sides: 3 = G and then B = G+4 = 7 So number of children in the family = B+G = 7+3 = 10.
The B. G. was born on September 3, 1980.
i am in 6th grade. my teacher taught us how to play the recorder and a few weeks more, my friends told me to play the dynamite. everyone was like SO clapping and they told me to play again! they even told me to right the notes!! so if you guys wanted the notes, here: 1 1 1 1 2 3 2 1 6 5 3 2 3 5 3 2 3 5 (repeat 2x) 3 3 3 3 3 3 3 3 3 3 3 3 3 3 5 3 2 1 6 5 (repeat 2x) hope this helps.
B. G. S. Ellett has written: 'The capacity of British Standard road gullies'
The Notorious B. I. G. was born on May 21, 1972.
Intro: g-g-a-a-a-a-a-a c-c-g-g-a-a-a Verse: g-g-g-g g-g-g-c g-g-g-g-g-g-g-g-g-a-b-a Refrain/Bridge: g-b-d-e-d-b-b-b-b-a g-b-d-e-d-b-a Chorus: b-b-a-g-g-g-g-g-g-a-b-a b-b-a-g-g-g-g-g-g-a-b-a b-b-a-g-g-g-g-g-g-b-a-a b-b-a-g-a-b b-b-b-b-b-a-g-g-g-g-g-g-a-b-a b-b-a-g-g-g-g-g-g-a-b-a b-b-a-g-g-g-g-g-g-b-a-a b-b-a-g-a-b b-b-b-b-b-a-g-a-b b-b-b-b-b-a-g
A string; D (3) C# (2) B (1) rest (crochets) D (3) C# (2) B (1) rest (crochets) B (1) B (1) B (1) B (1) C# (2) C# (2) C# (2) C# (2) (quavers) D (3) C# (2) B (1) rest (crochets) D- note (2) - finger Music is set out in 4/4 time. 1 bar per line.