3nAHCO 3 plus h3 C6 H5 07 nA3c6h507 plus 3CO2 plus 3H20?

Answer 1

3NaHCO3 + H3C6H5O7 = 3CO2 + 3H2O + Na3C6H5O7? 3NaHCO3 + H3C6H5O7 = 3CO2 + 3H2O + Na3C6H5O7

How many moles of carbon dioxide can be produced if one tablet containing 0.0124 mol NaHCO3 is dissolved?

is this your question?

If so then , okay, first, since the 3CO2 is coming solely from the 3NaHCO3, you need to break those parts of the equation down to their constituent moles. We ignore the prefix (3) cos it is equal in both molecules.

NaHCO3:

1 molecule of Na (Sodium) = 23

1 molecule of H (Hydrogen) = 1

1 molecule of C (Carbon) = 12

3 molecules of O (Oxygen) = 16 X 3 = 48

Total = 84

CO2:

1 molecule of C (carbon) = 12

2 molecules of O (oxygen) = 16 X 2 = 32

Total = 44

Since one tablet contains 0.0124 moles of NaHCO3, it follows therefore that the amount of CO2 produced will be:

84 moles amounts to 0.0124

Therefore 44 should amount to how much?

(use simple proportion to calculate):

(44 / 84) X 0.0124

= 0.00649

~ 0.0065 moles.

So from the dissolution of a tablet containing 0.0124 moles NaHCO3, will produce 0.0065 moles of CO2.