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The equation 3X-12=X+24 can be solved using basic algebra. First we put all the variables (X) on one side. So we minus X from both sides to get rid of the X on the right side resulting in 2X-12=24. Now we add 12 to both sides to get rid of the constant (12) on the left side resulting in 2X=36. Now divide both sides by 2 to get X by itself: X=18.

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Q: 3x-12 equals x plus 24
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