The equation 3X-12=X+24 can be solved using basic algebra. First we put all the variables (X) on one side. So we minus X from both sides to get rid of the X on the right side resulting in 2X-12=24. Now we add 12 to both sides to get rid of the constant (12) on the left side resulting in 2X=36. Now divide both sides by 2 to get X by itself: X=18.
x=6Solution:x + 2x + 14 = 5x + 214 - 2 = 5x - 3x12 = 2xx = 12/2 = 6
x equals 25
X equals 9.
x=-24
75
x=6Solution:x + 2x + 14 = 5x + 214 - 2 = 5x - 3x12 = 2xx = 12/2 = 6
x equals 25
X equals 9.
x=-24
24 + 24 + 24 + 24 = 24 x 4 = 96
75
X = -24. -24+7=-17+14=-3
5x+3+x=24 6x+3=24 6x=21 x=3.5
24 24 + (-15) = 9
-8
No.
x = 8