6
To solve the system of equations (3x + 9y = -18) and (-3x + 10y = 18) by elimination, we can add the two equations together to eliminate (x). This results in ( (3x - 3x) + (9y + 10y) = -18 + 18), simplifying to (19y = 0), which gives (y = 0). Substituting (y = 0) back into either equation, such as (3x + 9(0) = -18), results in (3x = -18), leading to (x = -6). Thus, the solution is (x = -6) and (y = 0).
-3x+7=2x-18 ---> 7+18=2x-3x ----> 25=5x ----> x=5
3x=18 x=18/3 x=6
3x-18 = 9 Adding 18 on both the sides we get, 3x = 27 Dividing both sides by 3 we get, x = 9.
If x-3x=18 then x equals -9
3x+12 = 18 3x = 18-12 3x = 6 x = 2
If: 3x+6 = 18 Then: x = 4
6-3x+12=0 6+12-3x=0 18-3x=0 18=3x x=6
-3x+7=2x-18 ---> 7+18=2x-3x ----> 25=5x ----> x=5
3x=18 x=18/3 x=6
3x-18 = 9 Adding 18 on both the sides we get, 3x = 27 Dividing both sides by 3 we get, x = 9.
4x+6-7x+9=18-3x+15=18-3x=3x=-1
If x-3x=18 then x equals -9
18=3(3x-6)
3x = 18divide both sides by 3x = 6
-3x+14 = -4 -3x = -4-14 -3x = -18 x = 6
4=3x-14 18=3x I carried the 14 over and it became positive. x=6 I divided 18 by 3.