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Presumably this is a simultaneous equation question in the form of:
3x+6y = 48
-5x+6y = 32
Subtract the bottom equation from the top equation in order to eliminate y. Note that 3x - - 5x is equal to + 8x:
8x = 16
Divide both sides by 8 to find the value of x:
x = 2
Substitute the value of x into the original equations to find the value y:
Therefore: x = 2 and y = 7
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When using substitution What is x and y for 3x plus 6y equals 48 -5x plus 6y equals 32?
3x + 6y = 48 .... Eq.1-5x + 6y = 32 .... Eq.2 .... in another way 6y = 5x + 32Put the value of Eq.2 in Eq. 13x + 5x + 32 = 488x = 48 - 328x = 16x = 16/8 ...... X = 2To find the value of Y put the value of X in Eq.26y = 5x + 326y = 5(2) + 326y = 10 + 326y = 42y = 42/6 ...... Y + 7
What is the answer for 3x plus 6 equals 54?
This is elementary stuff: 3x + 6 = 54 Subtract 6 from each side: 3x = 48 Divide each side by 3: x = 16.
48 plus 48 plus 48 equals?
144
What is x if 3X plus 13 equals 61-3X?
3x + 13 = 61 - 3x : add 3x to both sides 6x + 13 = 61 : deduct 13 from both sides 6x = 48 : divide both sides by 6 x = 8
What is 5x-30 equals 3x plus 2?
5X - 30 = 3X + 2 subtract 3X from both sides 5X - 3X - 30 = 3X - 3X + 2 2X - 30 = 2 add 30 to each side 2X - 30 + 30 = 2 + 30 2X = 32 divide both sides integers by 2 (2/2)X = 32/2 X = 16 -----------------check in original equation 5(16) - 30 = 3(16) + 2 80 - 30 = 48 + 2 50 = 50 checks
