Presumably this is a simultaneous equation question in the form of:
3x+6y = 48
-5x+6y = 32
Subtract the bottom equation from the top equation in order to eliminate y. Note that 3x - - 5x is equal to + 8x:
8x = 16
Divide both sides by 8 to find the value of x:
x = 2
Substitute the value of x into the original equations to find the value y:
Therefore: x = 2 and y = 7
32 plus 16 equals 48.
3x + 6y = 48 .... Eq.1-5x + 6y = 32 .... Eq.2 .... in another way 6y = 5x + 32Put the value of Eq.2 in Eq. 13x + 5x + 32 = 488x = 48 - 328x = 16x = 16/8 ...... X = 2To find the value of Y put the value of X in Eq.26y = 5x + 326y = 5(2) + 326y = 10 + 326y = 42y = 42/6 ...... Y + 7
This is elementary stuff: 3x + 6 = 54 Subtract 6 from each side: 3x = 48 Divide each side by 3: x = 16.
144
3x + 13 = 61 - 3x : add 3x to both sides 6x + 13 = 61 : deduct 13 from both sides 6x = 48 : divide both sides by 6 x = 8
3x+12=x+48: 3x-x=-12+48 2x=36 x=18
3x+5y=48 5y=48-3x-3x+5y=12 -3x+(48-3x)=12-6x=-36x=65y=48-3(6)5y=30y=6(6,6)
3x + 10x - 48 = 0 13x = 48 x = 3.692307692
32 plus 16 equals 48.
No. 16 + 32 = 48
3x + 6y = 48 .... Eq.1-5x + 6y = 32 .... Eq.2 .... in another way 6y = 5x + 32Put the value of Eq.2 in Eq. 13x + 5x + 32 = 488x = 48 - 328x = 16x = 16/8 ...... X = 2To find the value of Y put the value of X in Eq.26y = 5x + 326y = 5(2) + 326y = 10 + 326y = 42y = 42/6 ...... Y + 7
x² + 8x - 48 = (x + 12)(x - 4) x² + 8x + 48 = (4+(√32)i)(4-(√32)i)
This is elementary stuff: 3x + 6 = 54 Subtract 6 from each side: 3x = 48 Divide each side by 3: x = 16.
3x - 5 = 48 So 3x = 53 and x = 53/3 = 17.66...
48 + 32 = 80
144
3x + 13 = 61 - 3x : add 3x to both sides 6x + 13 = 61 : deduct 13 from both sides 6x = 48 : divide both sides by 6 x = 8