7z+9 = 72 7z = 72-9 7z = 63 z = 9
7z + 6s + s = 7z + 7s This can then be factorised using 7 as the factor: 7z + 7s = 7(z + s)
2z+9.75-7z=-5.15
z = -2
The answer to 2Z plus 9.75 subtract 7Z subtract equals 14.90. This is a math problem.
If Z = 3, then (9 + 7Z) = [ 9 + 7(3) ] = 9 + 21 = 30
x = Y + 7z
7z - 9.4 = 11.6 7z = 11.6 + 9.4 = 21 z = 21/7 = 3
7+7z 7=7*1 7z=7*z 7(1+z) is factored form
Zx(3+4)= Zx7 = 7z the answer is 7z
7z - 3 = 11 + 3z ie 7z -3z = 11 + 3 4z = 14 z = 3.5 Check: (7 x 3.5) - 3; 11 + (3 x 3.5) 24.5 - 3 = 11 + 10.5 21.5 = 21.5 QED
3x-3y+7z