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4/5d=32

We move all terms to the left:

4/5d-(32)=0

Domain of the equation: 5d!=0

d!=0/5

d!=0

d∈R

We multiply all the terms by the denominator

-32*5d+4=0

Wy multiply elements

-160d+4=0

We move all terms containing d to the left, all other terms to the right

-160d=-4

d=-4/-160

d=1/40

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Q: 4/5d= 32
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