Q: 4 plus 10 plus 16 plus plus 70 find the sum of this series?

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The sum of 10 plus 8 is 18.

10 print "That is not a question." 20 print "That is a command." 30 end

the sum of 10 + 10 = 20

4 plus 10 = 14

10

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The sum of 10 plus 8 is 18.

10 print "That is not a question." 20 print "That is a command." 30 end

the sum of 10 + 10 = 20

the sum of 80 + 20 + 90 + 10 = 200

The sum answer = 3440

4 plus 10 = 14

#include<iostream> unsigned sum_of_digits(unsigned num) { unsigned sum = 0; do { sum += num%10; } while(num/=10); return sum } int main() { unsigned num = 42; unsigned sum = sum_of_digits (num); std::cout << sum; // output: 6 }

the sum of 1 plus 9 is 10 because 1+9

Capacitors in series: (1/Total) = 1/A + 1/B 1/Total = (B + A) / AB Total = AB/(A+B) = (Product)/(Sum), if only twocapacitors in series. We have 4uf and 6 uf. Product = (4 x 6) x 10-12 = 2.4 x 10-11 Sum = (4 + 6) x 10-6 = 1 x 10-5 Product/sum = (2.4 x 10-11) / (1 x 10-5) = 2.4 x 10-6 = 2.4 uf ======================================== Easier:Total = product/sum = (4 x 6) / (4 + 6) = 24/10 = 2.4 uf

7+3+10 = 20

7+10=17

It is: 10 plus 51 = 61