Presumably this is a simultaneous equation question in the form of:
4x-y = 32
4x+5y = -16
Subtract the bottom equation from the top equation remembering that a -- is equal to a + so 32--16 is +40 and that -+5y-y is -6y:
-6y = 48
Divide both sides by -6 to find the value of y:
y = -8
Substitute the value of y into the original equations to find the value of x:
So: x = 6 and y = -8
16-9+32=16
27a + 16 = ba = 32(27 x 32) + 16 = b864 + 16 = bb = 880
4x+32=-4x+16x4x+32=12x-4x -4x32=8x/8 /84=x
You plug in the values of x and y and solve 12x + 16y = ? 12(1) + 16(2) = 12 + 32 = 44
8x2 + 16x + 8 = 8*(x2 + 2x + 1) = 8*(x + 1)2
No. 16 + 32 = 48
2048
16-9+32=16
27a + 16 = ba = 32(27 x 32) + 16 = b864 + 16 = bb = 880
50
4x+32=-4x+16x4x+32=12x-4x -4x32=8x/8 /84=x
k - 32 = 16 - 2 + 4 so k - 32 = 18 and then k = 18 + 32 = 50
The answer to that is simple: 32. 16 +16 _____ 32
32+90+16=138
32+14+20+18+16+31+21+16=168
2 + 2 + 32 = 36
p + 32