4x2 + 28x + 49 = 4x2 + 14x + 14x + 49 = 2x(2x + 7) + 7(2x + 7) = (2x + 7)(2x + 7) or (2x + 7)2
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49 Check when:- 4x2-28x+49 = 0 (2x-7)(2x-7) = 0 x = 7/2 and also x = 7/2
(2x-7)(2x-7) = area 4x2-28x+49 = area
(4x + 7)(16x2 - 28x + 49)
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4x^(2) + 28xy + 49y^(2) -> (2x)^(2) + 28xy + (7y)^2 Split into brackets ( 2x + 7y)(2x + 7y) If you applyuFOIL you will find toy come to '28xy'. The clue to this problem is to note that '4' ^ '49' are both squared numbers.