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What is the measure of the third side of a triangle where the perimeter is 8X plus 4Y and the others are X plus 2Y and 3X plus Y?
The perimeter of the triangle is 8x + 4y. The measures of two of the sides are x + 2y and 3x + y. If these two sides were added together, they would be 4x + 3y:x + 2y3x + y4x + 3yThe third side is the perimeter minus the two known sides, so 8x + 4y - (4x + 3y). Distribute the negative: 8x + 4y - 4x - 3y. This is equal to the third side, which is 4x +y.
How much is (2x plus 3y) plus (4x plus y)?
It is the same as: 6x+4y
You write 4x plus 4y equals 40?
How do you write 4x plus 4y equals 40 or how do you solve it? You would write it 4x+4y=40 you would solve it for y by subtracting 4x from both sides 4y=40-4x then divide all of that by 4y=40-4x/4 that's if you were graphing i have no idea what you're asking hope that helps if it's not too late.
What is this equation in standard form 4y equals -6 plus 4x?
In standard form it is 4x - 4y = 6 or 2x - 2y = 3
What is this expression but simplified 3x minus 4y minus x plus 6y plus 2 plus 4x?
Collect like terms: 3x - x + 4x - 4y + 6y + 2 = 6x + 2y + 2
