4X2+X3+3X+7Y+2X3 can only be simplified to 3X3+4X2+3X+7Y, because X3 and 2X3 are the only like terms.
You can expand the first expression in parentheses, then add or subtract like terms.
4x2 - 20x + 16 = 4(x2 - 5x + 4) = 4(x - 1)(x - 4)
This may be copied wrong, but as written that equals 4x^2-15x which factors to x(4x - 15)
Use www.wolframalpha.com Enter factor 4x^2+8x-5 to receive the answer (2x-1)(2x+5)
To determine the number of real solutions for the equation (4x^2 + 16x + 16 = 0), we can use the discriminant (D = b^2 - 4ac). Here, (a = 4), (b = 16), and (c = 16). Calculating the discriminant gives (D = 16^2 - 4(4)(16) = 256 - 256 = 0). Since the discriminant is zero, there is exactly one real solution to the equation.
(2x - 5)(2x - 3)
Answer is x2 -6x+14 with remainder 2
68
It is a quadratic equation and the values of x are: -1/2 and 6
No, anything that is x^2 and y^2 is circular.
-30xcubed times y to the power of 5
-30xcubed times y to the power of 5
You can expand the first expression in parentheses, then add or subtract like terms.
This may be copied wrong, but as written that equals 4x^2-15x which factors to x(4x - 15)
4x2 - 20x + 16 = 4(x2 - 5x + 4) = 4(x - 1)(x - 4)
Use www.wolframalpha.com Enter factor 4x^2+8x-5 to receive the answer (2x-1)(2x+5)
To determine the number of real solutions for the equation (4x^2 + 16x + 16 = 0), we can use the discriminant (D = b^2 - 4ac). Here, (a = 4), (b = 16), and (c = 16). Calculating the discriminant gives (D = 16^2 - 4(4)(16) = 256 - 256 = 0). Since the discriminant is zero, there is exactly one real solution to the equation.