It has volume √187200 cm³ which is approx 432.7 cu cmIt has dimensions: √(276 12/13) cm by √(36 1/9) cm by √(18 18/25) cmwhich is approx: 16.6 cm by 6 cm by 4.3 cm--------------------------------------------------------------------How this is solved:It has the dimensions of a cuboid are length, width and depth.Thus the three adjacent faces are given by:length × width = 100 cm²width × depth = 72 cm²depth × length = 26 cm²Multiplying all three equations together gives:(length × width) × (width × depth) × (depth × length) = 100 cm² × 72 cm² × 26 cm²→ length² × width² × depth² = 187200 cm^6→ (length × width × depth)² = (187200 cm³)²→ length × width × depth = √187200 cm³But for a cuboid:volume = length × width × depth = √187200 cm³ ≈ 432.7 cu cmGoing back to the original three equations above, rearranging (3):3) depth × length = 26 cm²→ depth = 26 cm² ÷ lengthSubstituting in (2):2) width × depth = 72 cm²→ width × (26 cm² ÷ length) = 72 cm²→ width = 72/26 × lengthSubstituting in (1):1) length × width = 100 cm²→ length × (72/26 × length) = 100 cm²→ length² = 2600/72 cm²→ length = √(36 1/9) cm ≈ 6 cmSubstituting in (3):3) depth × length = 26 cm²→ depth × sqrt(36 1/9) cm= 26 cm²→ depth = 26 ÷ sqrt(36 1/9) cm→ depth = √(18 18/25) cm ≈ 4.3 cmSubstituting in (2):2) width × depth = 72 cm²→ width × sqrt(18 18/25) cm = 72 cm²→ width = 72 ÷ sqrt(18 18/25) cm→ width = √(276 12/13) cm ≈ 16.6 cmNote that length, width and depth can be any of the three dimensions; the cuboid has dimensions:√(276 12/13) cm by √(36 1/9) cm by √(18 18/25) cmwhich is approximately:16.6 cm by 6 cm by 4.3 cm
0.9 m in 900 cm
The perimeter is 120 cm
you need three measurements...the height,width an depth of the pool..volume in litres = height (cm)x width(cm)x depth(cm) /1000
You can't.From the information given you can calculate that the width times the depth is 60 cm2 .There is no way to know what the width is.
It has volume √187200 cm³ which is approx 432.7 cu cmIt has dimensions: √(276 12/13) cm by √(36 1/9) cm by √(18 18/25) cmwhich is approx: 16.6 cm by 6 cm by 4.3 cm--------------------------------------------------------------------How this is solved:It has the dimensions of a cuboid are length, width and depth.Thus the three adjacent faces are given by:length × width = 100 cm²width × depth = 72 cm²depth × length = 26 cm²Multiplying all three equations together gives:(length × width) × (width × depth) × (depth × length) = 100 cm² × 72 cm² × 26 cm²→ length² × width² × depth² = 187200 cm^6→ (length × width × depth)² = (187200 cm³)²→ length × width × depth = √187200 cm³But for a cuboid:volume = length × width × depth = √187200 cm³ ≈ 432.7 cu cmGoing back to the original three equations above, rearranging (3):3) depth × length = 26 cm²→ depth = 26 cm² ÷ lengthSubstituting in (2):2) width × depth = 72 cm²→ width × (26 cm² ÷ length) = 72 cm²→ width = 72/26 × lengthSubstituting in (1):1) length × width = 100 cm²→ length × (72/26 × length) = 100 cm²→ length² = 2600/72 cm²→ length = √(36 1/9) cm ≈ 6 cmSubstituting in (3):3) depth × length = 26 cm²→ depth × sqrt(36 1/9) cm= 26 cm²→ depth = 26 ÷ sqrt(36 1/9) cm→ depth = √(18 18/25) cm ≈ 4.3 cmSubstituting in (2):2) width × depth = 72 cm²→ width × sqrt(18 18/25) cm = 72 cm²→ width = 72 ÷ sqrt(18 18/25) cm→ width = √(276 12/13) cm ≈ 16.6 cmNote that length, width and depth can be any of the three dimensions; the cuboid has dimensions:√(276 12/13) cm by √(36 1/9) cm by √(18 18/25) cmwhich is approximately:16.6 cm by 6 cm by 4.3 cm
9m is 900cm
900cm
900cm
4cm in width
It is 1780 cm.
0.9 m in 900 cm
The perimeter is 120 cm
you need three measurements...the height,width an depth of the pool..volume in litres = height (cm)x width(cm)x depth(cm) /1000
32 cm3
100 cm = 1 meter 900 cm = 9 meters
20cm.