52% of 71= 52% * 71= 0.52 * 71= 36.92
53, 59, 61, 67, 71 and 73 are the prime numbers between 52 and 76.
175 = 52 x 71
53 59 61 67 71 73.
53 59 61 67 71 73.
52% of 71= 52% * 71= 0.52 * 71= 36.92
19 + 52 = 71
Mean = (63+65+52+71+67+52)/6 = 370/6 = 61.66... recurring.
If 52 + y = 71 = then y MUST equal 19 !
Tellurium-123 has 52 protons and 71 neutrons. This is determined by the atomic number and mass number of tellurium (52 protons and 123 total nucleons).
71. My method: 52 + 19 = 52 + (20 - 1) = (52 + 20) - 1 = 72 - 1 = 71 Of course, I do not go through each step!
The "52" describes the order in which that specific bomber "B" went into service. Numbering ranges from 1 to 71 with 71 being given the prefix "SR" for strategic reconnaissance.
The answer is: 1
4(x2 - 6x + 13)
53, 59, 61, 67, 71 and 73 are the prime numbers between 52 and 76.
Median means average, and range is the range of numbers in a group. For example, the range is from 52 to 71. I don't know what a mode is.
175 = 52 x 71