1 x 55 = 55 1 x 60 = 60 2 x 60 = 120 3 x 60 = 180 2 x 55 = 110 3 x 55 = 165 4 x 55 = 220 5 x 55 = 275 6 x 55 = 330 7 x 55 = 385 8 x 55 = 440 9 x 55 = 495 10 x 55 = 550
1 x 55=55 5 x 11=55
1 x 55 = 55 5 x 11 = 55
to solve this answer plz go to the bottom of this : 55 x 1 = 55 2 x 55 = 110 3 x 55 = 165 4 x 55 = 220 5 x 55 = 275 6 x 55 = 330 7 x 55 = 385 8 x 55 = 440 9 x 55 = 495 10 x 55 = 550 11 x 55 = 605 12 x 55 = 660 THANKS !
55 = (5 x 10) + (5 x 1)
1 x 55, 5 x 11, 11 x 5, 55 x 1
The factors of 55 are: 1, 5, 11, 55 1 x 55 = 55 5 x 11 = 55
1 x 55 = 55 1 x 60 = 60 2 x 60 = 120 3 x 60 = 180 2 x 55 = 110 3 x 55 = 165 4 x 55 = 220 5 x 55 = 275 6 x 55 = 330 7 x 55 = 385 8 x 55 = 440 9 x 55 = 495 10 x 55 = 550
1 x 55=55 5 x 11=55
The factors of 55 are 5 X 11 or 11 X 5 and 55 X 1 or 1 X 55
1 x 55 = 55 5 x 11 = 55
55 = 1 x 55 55 = 5 x 11
The first six positive integer multiples of 55 are: 1 x 55 = 55 2 x 55 = 110 3 x 55 = 165 4 x 55 = 220 5 x 55 = 275 6 x 55 = 330
to solve this answer plz go to the bottom of this : 55 x 1 = 55 2 x 55 = 110 3 x 55 = 165 4 x 55 = 220 5 x 55 = 275 6 x 55 = 330 7 x 55 = 385 8 x 55 = 440 9 x 55 = 495 10 x 55 = 550 11 x 55 = 605 12 x 55 = 660 THANKS !
Algebraically. X = consecutive numbers. X + (X + 1) = 55 2X + 1 = 55 2X = 54 X = 27 =======so, X + 1 = 28 ==== (27, 28) -------------------solution set
1 x 55, 5 x 11.
55 = (5 x 10) + (5 x 1)