1 x 55 = 55 1 x 60 = 60 2 x 60 = 120 3 x 60 = 180 2 x 55 = 110 3 x 55 = 165 4 x 55 = 220 5 x 55 = 275 6 x 55 = 330 7 x 55 = 385 8 x 55 = 440 9 x 55 = 495 10 x 55 = 550
1 x 55=55 5 x 11=55
1 x 55 = 55 5 x 11 = 55
to solve this answer plz go to the bottom of this : 55 x 1 = 55 2 x 55 = 110 3 x 55 = 165 4 x 55 = 220 5 x 55 = 275 6 x 55 = 330 7 x 55 = 385 8 x 55 = 440 9 x 55 = 495 10 x 55 = 550 11 x 55 = 605 12 x 55 = 660 THANKS !
55 = (5 x 10) + (5 x 1)
1 x 55, 5 x 11, 11 x 5, 55 x 1
The factors of 55 are: 1, 5, 11, 55 1 x 55 = 55 5 x 11 = 55
1 x 55 = 55 1 x 60 = 60 2 x 60 = 120 3 x 60 = 180 2 x 55 = 110 3 x 55 = 165 4 x 55 = 220 5 x 55 = 275 6 x 55 = 330 7 x 55 = 385 8 x 55 = 440 9 x 55 = 495 10 x 55 = 550
1 x 55=55 5 x 11=55
The factors of 55 are 5 X 11 or 11 X 5 and 55 X 1 or 1 X 55
55 = 1 x 55 55 = 5 x 11
1 x 55 = 55 5 x 11 = 55
The first six positive integer multiples of 55 are: 1 x 55 = 55 2 x 55 = 110 3 x 55 = 165 4 x 55 = 220 5 x 55 = 275 6 x 55 = 330
to solve this answer plz go to the bottom of this : 55 x 1 = 55 2 x 55 = 110 3 x 55 = 165 4 x 55 = 220 5 x 55 = 275 6 x 55 = 330 7 x 55 = 385 8 x 55 = 440 9 x 55 = 495 10 x 55 = 550 11 x 55 = 605 12 x 55 = 660 THANKS !
Algebraically. X = consecutive numbers. X + (X + 1) = 55 2X + 1 = 55 2X = 54 X = 27 =======so, X + 1 = 28 ==== (27, 28) -------------------solution set
If you include fractions and decimals, then there are aninfinite number of such pairs, so they can't be listed.If you're satisfied to limit the discussion to whole numbers,then the pairs are:1 x 555 x 11-1 x -55-5 x 11
1 x 55, 5 x 11.