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Assuming you mean (5/31)/(15/23) the answer is 115/466 if my math is right. With divisions of fractions you can set it up as a multiplication, but you invert the second fraction. Here is an example: 5/31 divided by 15/23 is the same as 5/31 x 23/15 due to the properties of fractions. so 5 x 23 = 115 and 31 x 15 = 466, so the answer is 115/466. There may be a reduction, but I havent looked for any divisible factors.

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Q: 5 over 31 divided by 15 over 23?
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Related questions

What is the quotient of 5 over 31 divided by 15 over 23?

5/31 ÷ 15/23 = 23/93


What is 5 over 31 divided by 15 over 23?

23/93


The quotient of 5 over 31 divided by 15 over 23 reduced to the lowest fracton is?

5/31 ÷ 15/23 = 23/93


The quotient of 5 over 31 divided by 15 over 23 reduced to the lowest fraction is?

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What is the quotient of 5 over 31 divided by 15 over 23 reduced to the lowest fraction ishat is?

23/93 (allready reduced)


What is five thirty firsts divided by fifteen twenty thirds?

(5/31) / (15/23) = (5/31)*(23/15) = (5*23)/(31*15) = (1*23)/(31/3) = 23/93


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When a number is divided by 837 the remainder is 643 what will be the remainder if the same number is divided by 31?

23. If the remainder when a number n is divided by m is r, then it is written as n ≡ r MOD m (read as "n is equivalent to r modulo m") and n = mk + r for some integer k. if n ≡ 643 MOD 837, then n = 837k + 643 (for some k) When n is divided by 31: n ÷ 31 = (837k + 643) ÷ 31 = 837k ÷ 31 + 643 ÷ 31 = 27k + 20 + 23/31 Multiplying both sides by 31: → n = 31 x (27k + 20) + 31 x 23/31 = 31m + 23 (where m = 27k + 20) → n ≡ 23 MOD 31 Thus the remainder when the same number is divided by 31 is 23.


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