Assuming you mean (5/31)/(15/23) the answer is 115/466 if my math is right. With divisions of fractions you can set it up as a multiplication, but you invert the second fraction. Here is an example: 5/31 divided by 15/23 is the same as 5/31 x 23/15 due to the properties of fractions. so 5 x 23 = 115 and 31 x 15 = 466, so the answer is 115/466. There may be a reduction, but I havent looked for any divisible factors.
23/93 (allready reduced)
(5/31) / (15/23) = (5/31)*(23/15) = (5*23)/(31*15) = (1*23)/(31/3) = 23/93
19 You can do this on google by entering (15+23+31+15+11)/5
31
23. If the remainder when a number n is divided by m is r, then it is written as n ≡ r MOD m (read as "n is equivalent to r modulo m") and n = mk + r for some integer k. if n ≡ 643 MOD 837, then n = 837k + 643 (for some k) When n is divided by 31: n ÷ 31 = (837k + 643) ÷ 31 = 837k ÷ 31 + 643 ÷ 31 = 27k + 20 + 23/31 Multiplying both sides by 31: → n = 31 x (27k + 20) + 31 x 23/31 = 31m + 23 (where m = 27k + 20) → n ≡ 23 MOD 31 Thus the remainder when the same number is divided by 31 is 23.
5/31 ÷ 15/23 = 23/93
23/93
5/31 ÷ 15/23 = 23/93
23/93
23/93 (allready reduced)
(5/31) / (15/23) = (5/31)*(23/15) = (5*23)/(31*15) = (1*23)/(31/3) = 23/93
5.7419
19 You can do this on google by entering (15+23+31+15+11)/5
31
23. If the remainder when a number n is divided by m is r, then it is written as n ≡ r MOD m (read as "n is equivalent to r modulo m") and n = mk + r for some integer k. if n ≡ 643 MOD 837, then n = 837k + 643 (for some k) When n is divided by 31: n ÷ 31 = (837k + 643) ÷ 31 = 837k ÷ 31 + 643 ÷ 31 = 27k + 20 + 23/31 Multiplying both sides by 31: → n = 31 x (27k + 20) + 31 x 23/31 = 31m + 23 (where m = 27k + 20) → n ≡ 23 MOD 31 Thus the remainder when the same number is divided by 31 is 23.
46. 46 divided by 2 = 23. 23 + 8 = 31.
0.0371