The expression you provided, "5x 2y-1 x-1y," seems to contain some typographical errors or missing operators. If you're looking to simplify or evaluate an expression involving these variables, please clarify the intended operations (e.g., multiplication, addition) and the correct arrangement of terms. For example, it might be interpreted as (5x \cdot (2y - 1) \cdot (x - y)). Please provide more details for a precise answer.
45-5x = 5x+55 -5x-5x = 55-45 -10x = 10 x = -1
2X2+5x-12 4+5x-12 -8+5x 5x-8
To do this equation, there would have to be an = in it. If you mean 5x-2y=4, then: 5x-2y=4 -5x -5x = -2y=4-5x Hope this helped!
-4x - 5x
5X = Y12 ???? If so...., Y12 = 5X Y = 12th root(5X) ===============
5x-5x = 0
10
0
45-5x = 5x+55 -5x-5x = 55-45 -10x = 10 x = -1
10x - 5x + 5x = 10x
5x+5x-10 10x-10 is the only answer you can get from this
-10x + 5x = -5x
2X2+5x-12 4+5x-12 -8+5x 5x-8
25x2 + 40x + 16 = 25x2 + 20x + 20x + 16 = 5x(5x + 4) + 4(5x + 4) = (5x + 4)(5x + 4) or (5x + 4)2
To do this equation, there would have to be an = in it. If you mean 5x-2y=4, then: 5x-2y=4 -5x -5x = -2y=4-5x Hope this helped!
0
-4x - 5x