x < 2
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8(1+5x) +5 = 13+5x => 8+40x + 5 = 13 +5x => 13+40x = 13+5x => 13-13+40x = 13-13+5x => 40x = 5x => 40x - 5x = 0 => 35x = 0 => 35x/35 = 0/35 => x = 0
4x + 5 < 5x + 3 5 < x + 3 x > 2
5x+49 = 8x+13 49-13 = 8x-5x 36 = 3x x = 12
3x+7=5x-13 ----> 3x-5x=-13-7 ----> -2x=-6 -----> x=3
It has no solutions because the discriminant of the quadratic equation is less than zero.