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64 S on C B?
64 squares on a chess board
What is the area of oblique triangles?
Use the Hero's formula: Let s = (a + b + c)/2. Then the area of the triangle equals√[s(s - a)(s - b)(s - c)], where a, b, and c denote the sides of the triangle.
How do you find the area of an oblique triangle which 3 sides are given?
Let the sides be a, b, c Area = sq rt [s(s-a)(s-b)(s-c)] where s= 1/2 (a+b+c)
What is the area of a triangle 17m by 17m by 30m?
120 sq metres. To see how you get this answer, read on: If the sides are a, b and c, then calculate s = 0.5*(a+b+c) Then the area is sqrt[s*(s-a)*(s-b)*(s-c)]
What is the formula for the surface area and volume of a triangular prism?
The answer depends on the information that you do have. Suppose you know all the edge lengths: the three sides of the triangle are a, b and c and the length of the prism is d. Let s = (a + b + c)/2 Then the area of the triangular cross section is sqrt[s*(s-a)*(s-b)*(s-c)] square units. So, surface area = 2*sqrt[s*(s-a)*(s-b)*(s-c)] + d*(a+b+c) square units. Volume = sqrt[s*(s-a)*(s-b)*(s-c)]*d cubic units.
64 S on C B?
64 squares on a chess board
64 b and w s on a c b?
64 black and white squares ona chess board
What is 62 S on C B?
If it was 64 then it would be Squares on a Chess Board
What is 64- S on a C?
64 squares on a checkerboard
64 s on a c?
64 squares on a checkerboard
64 S on a C B?
64 Squares on a Chess/Checkers Board
64 s in a c?
64 squares in checkerboard (or chess board).
What does 64 S on a C mean?
64 squares on a chess board
What is the area formula for an triangle?
It is sqrt{s*(s-a)*(s-b)*(s-c)} where the lengths of the three sides are a, b and c units and s = (a+b+c)/2.
What is the area of a triangle when given are the length and the sides?
Suppose the sides are a, b and c units. Calculate s= (a+b+c)/2 Then Area = sqrt[s*(s-a)*(s-b)*(s-c)] square units
How do you find the area of an oblique triangle which 3 sides are given?
Let the sides be a, b, c Area = sq rt [s(s-a)(s-b)(s-c)] where s= 1/2 (a+b+c)
What is the area of oblique triangles?
Use the Hero's formula: Let s = (a + b + c)/2. Then the area of the triangle equals√[s(s - a)(s - b)(s - c)], where a, b, and c denote the sides of the triangle.
