64 squares on a chess board
The expression "64 s on a c b" likely refers to the phrase "64 seconds on a clock face" or "64 seconds on a countdown timer." If that's the case, the answer would depend on the context or the specific question being asked about this time duration. If you can provide more details or clarify the context, I would be happy to assist further!
Use the Hero's formula: Let s = (a + b + c)/2. Then the area of the triangle equals√[s(s - a)(s - b)(s - c)], where a, b, and c denote the sides of the triangle.
Let the sides be a, b, c Area = sq rt [s(s-a)(s-b)(s-c)] where s= 1/2 (a+b+c)
120 sq metres. To see how you get this answer, read on: If the sides are a, b and c, then calculate s = 0.5*(a+b+c) Then the area is sqrt[s*(s-a)*(s-b)*(s-c)]
64 squares on a chess board
64 black and white squares ona chess board
If it was 64 then it would be Squares on a Chess Board
The expression "64 s on a c b" likely refers to the phrase "64 seconds on a clock face" or "64 seconds on a countdown timer." If that's the case, the answer would depend on the context or the specific question being asked about this time duration. If you can provide more details or clarify the context, I would be happy to assist further!
64 squares on a checkerboard
64 squares on a checkerboard
64 Squares on a Chess/Checkers Board
64 squares on a chess board
64 squares in checkerboard (or chess board).
It is sqrt{s*(s-a)*(s-b)*(s-c)} where the lengths of the three sides are a, b and c units and s = (a+b+c)/2.
Suppose the sides are a, b and c units. Calculate s= (a+b+c)/2 Then Area = sqrt[s*(s-a)*(s-b)*(s-c)] square units
Use the Hero's formula: Let s = (a + b + c)/2. Then the area of the triangle equals√[s(s - a)(s - b)(s - c)], where a, b, and c denote the sides of the triangle.