That may be, but a single linear equation in three unknown variables cannot be solved.
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c-2b
ok, let's see: (3a-2a) + (2b+5b) +(-c +3c) = a + 7b +2c I think that's right.
20a plus 14 will be 34a minus 8a minus 7 34a minus 8 is 26a minus 7 is 19a. The single b is 1b plus 6b which is 7b minus 2b equals 5b.
In other words: 3x+y=2z+a x+3y=2b+3a z+y=3c+a (all equals:) c+y=b+a
a^2b^2(4ab) = 8a^3b^3.