Is 24u^2 + 35
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It is a linear equation in the variable u.
add 8 and 2 then take away 3. even u should get 7u.
For a suitable value of u, it can be.
Which can be factored by multiplying five 2's, fourteen u's, two w's and seventeen y's.
So you have (4^(x-2))^(x+1)=15. Using a law of exponents (b^a)^c=b^(a*c) and 4=2^2, you get 4^((x-2)*(x+1))=15=2^(2(x-2)(x+1)). Take log base two and use the rule about logs of products you get 2(x-2)(x+1)=Log_2(15) Simplifying and substituting u for Log_2(15), 2x^2-2x-4=u, which means 2x^2-2x-(4+u)=0, using quadratic formula. X=(1/4)(2(+or-)sqrt(4-4*2*(-4-u))) or (1/2) plus or minus (1/4)(sqrt(36+8u)) Where sqrt(b) is the square root of b