It is a linear equation in the variable u.
add 8 and 2 then take away 3. even u should get 7u.
For a suitable value of u, it can be.
Which can be factored by multiplying five 2's, fourteen u's, two w's and seventeen y's.
So you have (4^(x-2))^(x+1)=15. Using a law of exponents (b^a)^c=b^(a*c) and 4=2^2, you get 4^((x-2)*(x+1))=15=2^(2(x-2)(x+1)). Take log base two and use the rule about logs of products you get 2(x-2)(x+1)=Log_2(15) Simplifying and substituting u for Log_2(15), 2x^2-2x-4=u, which means 2x^2-2x-(4+u)=0, using quadratic formula. X=(1/4)(2(+or-)sqrt(4-4*2*(-4-u))) or (1/2) plus or minus (1/4)(sqrt(36+8u)) Where sqrt(b) is the square root of b
u = 7
It is a linear equation in the variable u.
13u
7u.
add 8 and 2 then take away 3. even u should get 7u.
-5u + 4 + 8u = 43simplify by subtracting 4 from both sides of the equation to get rid of the 4 on the left:-5u + 8u = 43Simplify further by combining the -5u and the 8u:3u = 43Divide both sides by 3 to solve for u:u = 43/3rewrite the fraction:u = 14 1/3
uhm...if u are talking about math then the answer is... -8u
40 feet for 16U 35 for 10U and moves to 43 feet in college
If: 8u = -96 Then: u = -12
Via Moskou (3u) naar Tokio (8u) = 11 uur. Via Kopenhagen = 1.5 + 10 = 11.5 uur. Via Singapore 13+6=19 uur. Minimaal 11 uur dus.
(8u)^5 = (8)^5 x (u)^5 = 32768xu^5
17