The answer will depend on whether the rotation is clockwise or counterclockwise.
ENE plus 90 degrees (clockwise) is SSE.
Assume we want to find the ordered pair after 90° counterclockwise rotation. From (x,y), we have (-y,x). If we want to find the ordered pair after 90° clockwise rotation, then from (x,y) we have (y, -x)
3 quarters clockwise is 270 degrees clockwise or 90 degrees anti(counter)-clocwise
The answer is A(-7, 2). To solve this problem, first convert the given points into vectors and then apply the given transformations. The vector for point T is (8, -5). After the half turn, the vector becomes (-5, -8). The vector for point W is (-2, -7). After a 90 degree clockwise rotation, the vector becomes (7, -2). The vector for point R is (6, -3). After a 90 degree counter-clockwise rotation, the vector becomes (-3, 6). Finally, the vector for point B is (-2, 7). After a 90 degree counter-clockwise rotation, the vector becomes (-7, 2). Therefore, the answer is A(-7, 2).
The answer will depend on whether the rotation is clockwise or anti-clockwise.
The answer will depend on whether the rotation is clockwise or counterclockwise.
The answer will depend on whether the rotation is clockwise or counterclockwise.
Rotation of 270 degrees clockwise or 90 degrees counter clockwise
A transformation, in the form of a rotation requires the centre of rotation to be defined. There is no centre of rotation given.
we swap the co-ordinates and give the new y co-ordinate the opposite sign.90 degrees clockwise(y, -x)
South. 90 degrees is 1/4 of a complete rotation, which is 360 degrees. http://www.mathsisfun.com/geometry/degrees.html
ENE plus 90 degrees (clockwise) is SSE.
Assume we want to find the ordered pair after 90° counterclockwise rotation. From (x,y), we have (-y,x). If we want to find the ordered pair after 90° clockwise rotation, then from (x,y) we have (y, -x)
rotate it 90 degrees
3 quarters clockwise is 270 degrees clockwise or 90 degrees anti(counter)-clocwise
The answer is A(-7, 2). To solve this problem, first convert the given points into vectors and then apply the given transformations. The vector for point T is (8, -5). After the half turn, the vector becomes (-5, -8). The vector for point W is (-2, -7). After a 90 degree clockwise rotation, the vector becomes (7, -2). The vector for point R is (6, -3). After a 90 degree counter-clockwise rotation, the vector becomes (-3, 6). Finally, the vector for point B is (-2, 7). After a 90 degree counter-clockwise rotation, the vector becomes (-7, 2). Therefore, the answer is A(-7, 2).