9, remainder 8
9% of 89= 9% * 89= 0.09 * 89= 8.01
Isolate the variable. Get it by itself. 9+11x=89+x 9+11x-1x=89+x-1x Subtraction property of equality 9+10x=89 9+10x-9=89-9 subtraction property of equality 10x=80 x=8 division property of equality.
As written it is: 89.99999999999999999999999999999999999999999 = 8999999999999999999999999999999999999999999/10000000000000000000000000000000000000000000 = 89 99999999999999999999999999999999999999999/100000000000000000000000000000000000000000 However, if that is meant to be 89.999... with the 9 recurring, then: 89.999... = 89 9/9 = 89 + 1 = 90. This can be seen if that is the result of addition of two recurring decimals when calculated using fractions, eg it could have been: 89.111... + 0.888... = 89.999... = 89 1/9 + 8/9 = 89 9/9 = 89 + 1 = 90 Thus 89.999... = 90
89% can be represented as 89/100. 8/9 = 88/99 = 8800/9900 Returning to 89% this can be represented as 89 x 99/100 x 99 = 8811/9900 Therefore 89 % is greater than 8/9 by 11/9900
No. 89 is not evenly divisible by nine.
9, remainder 8
9% of 89= 9% * 89= 0.09 * 89= 8.01
89 ÷ 16 = 5 with remainder 9 or 5.5625 times.
No, 89 is not divisible by 9.
9 divided into 89 = 0.10112359550561797
8 9/10. You people are real smart don't you know your math what do you go to school for talk smart one
9.8889
go ask your teacher and tell him hes dumb
89 divided by 9 = 9 with 8 leftover = 9.8
85
9.8889