n - 7 = 9
n = 16
9 - n
n 7
1/9 * (n - 15)the product of one-ninth and the difference of a number and fifteen:Let n = the number1/9 * (n - 15)
7*abs(n - 10) which is 7*(10 - n) if n < 10 and 7*(n - 10) if n ≥ 10
Let the numbers be 'n' & 'n+2' Their product is n(n+2) = 63 n^(2) + 2n = 63 n^(2) + 2n - 63 = 9 It is now in quadratic form ; factor ( n - 7)( n + 9) = 0 n + 2 = 9 n = 7 '7' & '9' are consecutive odd numbers.
7 - n
abs(9 - n) which is 9 - n if 9 ≥ n and n- 9 if 9 ≤ n
The way to write out the difference of 9 and a number is n-9.
7 more than the quotient of a number n and 4 is 9
9 - n
n 7
1/9 * (n - 15)the product of one-ninth and the difference of a number and fifteen:Let n = the number1/9 * (n - 15)
n-8
3 x (7 - n)
The difference between a number and its reverse must be divisible by 9. 42 is NOT divisible by 9. There is, therefore, no such number.
7*abs(n - 10) which is 7*(10 - n) if n < 10 and 7*(n - 10) if n ≥ 10
abs(n - 6) < 9.