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Each quarter is 25, and he has X quarters.

Each dime is 10, and he has 2X dimes.

Each nickel is 5. He has 12 coins in total, and all of the ones that are not quarters or dimes are nickels. Since quarters and dimes have to come in sets of 3, that's 12-3X.

25X + 10(2X) + 5(12-3X) = 120

25X + 20X - 15X + 60 =120

30X + 60 = 120

30X = 60

X = 2

He has 2 quarters, 4 dimes, and 6 nickels.

To double check let's add them up:

(2 * 25) + (4* 10) + (6 * 5) = 120

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Michael Scalise

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βˆ™ 3y ago
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Q: A man has a mixture of nickels dimes and quarters in his pocket. He has 12 coins in all with a total of $1.20. If he had twice as many dimes as quarters how many of each coin does he have?
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