225 days
A does 1/10 per day on his own, so in 6 days he's done 60%, leaving 40% done by B in 6 days. B will take 6 x 100/40 days on his own, ie 15 days
-- B can do the job alone in 16 days.-- So B does 1/16 of the job per day.-- In 6 days, B does 6/16 = 3/8 of the job.-- If A and B working together do the job in 6 days, then A does the other 5/8 of the job in 6 days.-- So A does 5/48 of the job each day.-- If they begin together, then after 3 days, A has done 5/16 and B has done 3/16.Together, they've finished 8/16 = 1/2 of the job. Not so surprising, when we recallthat it takes them 6 days to do the whole thing together.-- Half of the job then remains for A to finish on his own. Since he does 5/48 per day,he needs 24/5 = 4.8 days to finish off the last half.4.8 more days
job is 50 man days, so 2½ men in 20 days but you can't get half a man, (unless he only works for 20 half-days), so 3 men for 10 days and 2 men for the other 10.
260 days.
225 days
The whole job takes 16 days.If you carve up the job into 48 pieces, then (48/16) = 3 pieces were done each day,of which 'A' did 2 pieces and 'B' did 1 piece.Since 'A' does 2 pieces of work a day, and a whole job consists of 48 pieces,it takes him (48/2) = 24 days to do the whole job alone.
If a "certain number of men" less 10 takes 20 days (twice as long) to finish the piece of work, then the "certain number of men" who can finish the work in 10 days would 20. If it takes 10 men less twice as long to do the work, then twice 10 men (20) can finish the job in 10 days.
A does 1/10 per day on his own, so in 6 days he's done 60%, leaving 40% done by B in 6 days. B will take 6 x 100/40 days on his own, ie 15 days
Use ratios, 20/15 = 25/x Multiply 15 by 20, then divide by 25. So 25 men could finish a job in 12 days.
have focus & concentrate the work.
they don't work alone because as you said they're "many", so they are not alone.
-- B can do the job alone in 16 days.-- So B does 1/16 of the job per day.-- In 6 days, B does 6/16 = 3/8 of the job.-- If A and B working together do the job in 6 days, then A does the other 5/8 of the job in 6 days.-- So A does 5/48 of the job each day.-- If they begin together, then after 3 days, A has done 5/16 and B has done 3/16.Together, they've finished 8/16 = 1/2 of the job. Not so surprising, when we recallthat it takes them 6 days to do the whole thing together.-- Half of the job then remains for A to finish on his own. Since he does 5/48 per day,he needs 24/5 = 4.8 days to finish off the last half.4.8 more days
It might have been possible to answer the question is you had had the time to complete the question!
6
job is 50 man days, so 2½ men in 20 days but you can't get half a man, (unless he only works for 20 half-days), so 3 men for 10 days and 2 men for the other 10.
Stop posting questions on the internet and get to work. =)