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How do you find the base of a triangle when the height is 2 ft and the area is 3ft squared?
Area of a triangle = b x h/2, where b is the base and h is height. To solve for b, manipulate the formula to b = 2A/h, where A is the area. b = 2A/h = 2(3ft2)/2ft = 3ft
What is the area of the trapezoid?
(a + b)h divide by 2. Where A is the top and B is the base and H is the height.
What is the formula for area of a trapazoid?
Which of the following formulas is used to find the area of a trapezoid? Solution: 1/2 h(B+b) The area of a trapezoid is 1/2 times the height times the sum of both bases. h is the height, b is the top base and B is the bottom base. A trapezoid=1/2×h×(B+b)
Why does the area of a triangle quadruple when the sides are doubled?
Since the area is (length of base)*(height)/2 {call these dimensions B & H) A1 = B*H/2 With dimensions doubled, A2 = (2*B)*(2*H)/2 = 4*B*H/2 = 4*A1. By not simplifying to 2*B*H, it's easier to see that it is four times the original area. It is 4 times because the two length dimensions are multiplied, and 2 * 2 = 4.
Which of the following is the correct formula to calculate area of a trapezium?
Let's call the parallel sides A and B, and the distance between them as H. The area of the trapezium, or K, is (A+B)H/2. K = (A+B)H/2
