a base in the height is worth 2 in the base.... i don't honestly know what that means..... but that's what it means in math terms, the B = Base and the H= Height. You're welcome :D
Area of a triangle = b x h/2, where b is the base and h is height. To solve for b, manipulate the formula to b = 2A/h, where A is the area. b = 2A/h = 2(3ft2)/2ft = 3ft
To solve for the height ( h ) of the trapezoid, we start with the area formula ( A = \frac{1}{2}(a + b)h ). Rearranging this equation to isolate ( h ), we multiply both sides by 2: ( 2A = (a + b)h ). Then, we divide both sides by ( (a + b) ) to get ( h = \frac{2A}{a + b} ). Thus, the height ( h ) can be expressed as ( h = \frac{2A}{a + b} ).
(a + b)h divide by 2. Where A is the top and B is the base and H is the height.
Which of the following formulas is used to find the area of a trapezoid? Solution: 1/2 h(B+b) The area of a trapezoid is 1/2 times the height times the sum of both bases. h is the height, b is the top base and B is the bottom base. A trapezoid=1/2×h×(B+b)
Since the area is (length of base)*(height)/2 {call these dimensions B & H) A1 = B*H/2 With dimensions doubled, A2 = (2*B)*(2*H)/2 = 4*B*H/2 = 4*A1. By not simplifying to 2*B*H, it's easier to see that it is four times the original area. It is 4 times because the two length dimensions are multiplied, and 2 * 2 = 4.
One bird in the hand is worth two in the bush.
Since h^2 =a^2+b^2 and h=5 then a=2 and b=3 is a solution.
A = h/2*(a + b) So 2A/h = a + b and therefore, a = 2A/h - b
Area of a triangle = b x h/2, where b is the base and h is height. To solve for b, manipulate the formula to b = 2A/h, where A is the area. b = 2A/h = 2(3ft2)/2ft = 3ft
$100
A=30, B=15, H=4 A=30, B=12, H=5 A=30, B=2, H=30 1/2 b x h= Area
A = (B x h)/2 As h is four times longer than B, we get h = 4 x B Then A = (B x 4B)/2 = (4 x B2)/2 = 2 x B2 thus B=sqrt(A/2) and h=4 x B=4 sqrt(A/2)
2*(L*B + B*H + H*L) cubic units where L = length B = Breadth H = Height.
(a + b)h divide by 2. Where A is the top and B is the base and H is the height.
Which of the following formulas is used to find the area of a trapezoid? Solution: 1/2 h(B+b) The area of a trapezoid is 1/2 times the height times the sum of both bases. h is the height, b is the top base and B is the bottom base. A trapezoid=1/2×h×(B+b)
Since the area is (length of base)*(height)/2 {call these dimensions B & H) A1 = B*H/2 With dimensions doubled, A2 = (2*B)*(2*H)/2 = 4*B*H/2 = 4*A1. By not simplifying to 2*B*H, it's easier to see that it is four times the original area. It is 4 times because the two length dimensions are multiplied, and 2 * 2 = 4.
A=h(b+B) divided by 2 * * * * * where A = area h = vertical height b and B are the lengths of the parallel sides.