Area of a triangle = b x h/2, where b is the base and h is height. To solve for b, manipulate the formula to b = 2A/h, where A is the area. b = 2A/h = 2(3ft2)/2ft = 3ft
(a + b)h divide by 2. Where A is the top and B is the base and H is the height.
Which of the following formulas is used to find the area of a trapezoid? Solution: 1/2 h(B+b) The area of a trapezoid is 1/2 times the height times the sum of both bases. h is the height, b is the top base and B is the bottom base. A trapezoid=1/2×h×(B+b)
Since the area is (length of base)*(height)/2 {call these dimensions B & H) A1 = B*H/2 With dimensions doubled, A2 = (2*B)*(2*H)/2 = 4*B*H/2 = 4*A1. By not simplifying to 2*B*H, it's easier to see that it is four times the original area. It is 4 times because the two length dimensions are multiplied, and 2 * 2 = 4.
Let's call the parallel sides A and B, and the distance between them as H. The area of the trapezium, or K, is (A+B)H/2. K = (A+B)H/2
One bird in the hand is worth two in the bush.
Since h^2 =a^2+b^2 and h=5 then a=2 and b=3 is a solution.
A = h/2*(a + b) So 2A/h = a + b and therefore, a = 2A/h - b
Area of a triangle = b x h/2, where b is the base and h is height. To solve for b, manipulate the formula to b = 2A/h, where A is the area. b = 2A/h = 2(3ft2)/2ft = 3ft
A=30, B=15, H=4 A=30, B=12, H=5 A=30, B=2, H=30 1/2 b x h= Area
A = (B x h)/2 As h is four times longer than B, we get h = 4 x B Then A = (B x 4B)/2 = (4 x B2)/2 = 2 x B2 thus B=sqrt(A/2) and h=4 x B=4 sqrt(A/2)
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2*(L*B + B*H + H*L) cubic units where L = length B = Breadth H = Height.
(a + b)h divide by 2. Where A is the top and B is the base and H is the height.
Which of the following formulas is used to find the area of a trapezoid? Solution: 1/2 h(B+b) The area of a trapezoid is 1/2 times the height times the sum of both bases. h is the height, b is the top base and B is the bottom base. A trapezoid=1/2×h×(B+b)
Since the area is (length of base)*(height)/2 {call these dimensions B & H) A1 = B*H/2 With dimensions doubled, A2 = (2*B)*(2*H)/2 = 4*B*H/2 = 4*A1. By not simplifying to 2*B*H, it's easier to see that it is four times the original area. It is 4 times because the two length dimensions are multiplied, and 2 * 2 = 4.
A=h(b+B) divided by 2 * * * * * where A = area h = vertical height b and B are the lengths of the parallel sides.