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The horizontal component of the motion is irrelevant.

The ball starts with a vertical velocity of 0 metres per second and has an acceleration of 9.8 metres per second squared.

It travels 50 metres so s = 1/2*g*t^2

that is, 50 = 1/2*g*t^2

therefore t^2 = 10.2

and so t = 3.19 seconds.

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Q: A ball is thrown horizontaly at 20m s from a 50 meter high cliff how long does it take the ball to reach the ground?
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