Wiki User
ā 14y agoBy the Way, guys, this is based on the equation H= -16t2+vt+s
Wiki User
ā 14y agoThe answer will depend on what "it" is, and on what its initial velocity is.
No. What counts in this case is the vertical component of the velocity, and the initial vertical velocity is zero, one way or another.
This is a velocity question so u need to use uvaxt
height(s)=1/2(u+v)t 200=1/2(0+v)*1v=400ft/secu = initial speedv=final speed
19.6m
The initial velocity of a projectile affects its range by determining how far the projectile will travel horizontally before hitting the ground. A higher initial velocity will result in a longer range because the projectile has more speed to overcome air resistance and travel further. Conversely, a lower initial velocity will result in a shorter range as the projectile doesn't travel as far before hitting the ground.
Increasing the initial velocity of a projectile will increase both its range and height. Higher initial velocity means the projectile will travel further before hitting the ground, resulting in greater range. Additionally, the increased speed helps the projectile reach a higher peak height before it begins to descend back down.
Using the kinematic equation ( \text{final velocity}^2 = \text{initial velocity}^2 + 2 \times \text{acceleration} \times \text{distance} ) where final velocity is 0 (at the top) and initial velocity is 2.6 m/s, acceleration due to gravity is -9.8 m/sĀ², and distance is 100 m, you can solve for time to get approximately 5.02 seconds.
To find the initial velocity of the kick, you can use the equation for projectile motion. The maximum height reached by the football is related to the initial vertical velocity component. By using trigonometric functions, you can determine the initial vertical velocity component and then calculate the initial velocity of the kick.
The object's initial distance above the ground The object's initial velocity
The velocity of the tomato when it hits the ground will be determined by its initial velocity, the force of gravity acting upon it, and any air resistance. It will likely be accelerating towards the ground due to gravity until it reaches its terminal velocity upon impact.
The answer will depend on what "it" is, and on what its initial velocity is.
The ball is thrown with an initial velocity, and gravity slows it down as it rises. At its peak, the ball's velocity is zero before it begins to fall back to the ground. This is due to the balance between the initial force and gravity acting on the ball.
No. What counts in this case is the vertical component of the velocity, and the initial vertical velocity is zero, one way or another.
To answer this question one would need to know the rock's initial height and velocity.
This result is because the wet ball carries more inertia to weight ratio before hitting the ground , it then compresses, loses some of the liquid weight, becomes lighter, and because of the initial inertial force, can therefore leave the ground at a greater velocity
Assuming the acceleration due to gravity is -9.81 m/s^2, the time it takes for the baseball to hit the ground can be calculated using the formula: time = (final velocity - initial velocity) / acceleration. In this case, the final velocity will be 0 m/s when the baseball hits the ground. Calculating it would give you the time it takes for the baseball to hit the ground.