Q: A box contains five blue eight green and three yellow marbles If a marble is slected at random what is the probability that it is not blue?

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Probability of drawing a red marble = 4/16 = 1/4 Probability of drawing not a red marble = 1 - 1/4 = 3/4

There is a probability of 3 that it will be blue.

The probability of picking a green marble from a box that only contains blue marbles is zero.

probability of pulling out a purple marble = 20/85probability of NOT pulling out a purple marble = 1 - 20/85 = 65/85 = 13/17

We will assume that the bag contains 11 marbles (this is not a trick question!), so 4 are blue and 7 are not blue, so the probability of a color other than blue is 7/11.

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3/16

Probability of drawing a red marble = 4/16 = 1/4 Probability of drawing not a red marble = 1 - 1/4 = 3/4

There is a probability of 3 that it will be blue.

The probability of picking a green marble from a box that only contains blue marbles is zero.

2/6

probability of pulling out a purple marble = 20/85probability of NOT pulling out a purple marble = 1 - 20/85 = 65/85 = 13/17

The theoretical probability of randomly picking each color marble is the number of color marbles you have for each color, divided by the total number of marbles. For example, the probability of selecting a red marble is 3/20.

There are 13 marbles in total. The order is specified.P(1st is white and the 2ndis purple) = (7/13)(6/12) = (7/13)(1/2) = 7/26.

Since the box contains 16 marbles, seven of them white, then the probability of drawing one white marble is 7/16. If you replace the marble and draw again, the probability of drawing another white marble is still 7/16. The net probability of drawing two white marbles, while replacing the first, is 49/256.

3/5

We will assume that the bag contains 11 marbles (this is not a trick question!), so 4 are blue and 7 are not blue, so the probability of a color other than blue is 7/11.

80% chance, Or 40/50