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At the bottom, the car has kinetic energy of ½mv2. At the top, the car has kinetic energy of 0. If we ignore friction and wind resistance, the initial kinetic energy is converted to gravitational potential energy of mgh, where the m is again the mass of the car, g is the acceleration of gravity, and h is the vertical change in position of the car. Solving the two equations for h, we get

h=½v2/g=(0.5)(25 m/s)2/(9.8 m/s2)=31.888 m

To find the distance traveled along the road, we use a bit of trigonometry: sin(30°) = h/d = 0.5, so d = 2h = 63.776 meters

Of course, the actual value will be less, due to the friction and wind resistance that we ignored in our calculations.

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