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(x+3)2 + (y+4)2 = 4

Q: A circle is centered at the point -3 -4 and has a radius of length 2 What is its equation?

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x2 + y2 = 49

1.6667

Equation of the circle: (x+1)^2 +(y+3)^2 = 25

It is (x + 1)2 + (y - 3)2 = 42

Since the circle is centered at the origin, the equation of the circle is x2 + y2 = r2. So we have: x2 + y2 = (3/2)2 x2 + y2 = 9/4

Related questions

x2 + y2 = 25

x2 + y2= 16

x2 + y2 = 25

x2 + y2 = 36

x2 + y2 = 49

Equation of circle: (x+2)^2 +(y+3) = 49

1.6667

Equation of circle: (x-3)^2 +(y-2)^2 = 49

Equation of the circle: (x+1)^2 +(y+3)^2 = 25

Equation of the circle: (x+1)^2 +(y+3)^2 = 25

It is (x + 1)2 + (y - 3)2 = 42

Equation: (x+1)^2 +(y-3)^2 = 16