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L1: x-intercept point (5, 0), perpendicular to L2

L2: 2x + 8y = 10

2x + 8y = 10

8y = -2x + 10

y = (-2/8)x + 10/8

y = -(1/4)x + 5/4, m2 = -1/4 so that m1 = 4

y = mx + b, replace y with 0, m with 4, and x with 5

0 = 4(5) + b

0= 20 + b subtract 20 from both sides

-20 = b, the y-intercept of L1.

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14y ago

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