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A line touching an arc or circle at only one point perpendicular to the arcs?
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∙ 12y ago
tangent
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∙ 12y ago
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Arcs of a circle that have exactly one point in common are called what?
Adjacent Arcs
How do you find a point which is equidistant from a given pair of points?
Bisect two arcs above and below the given points or line and the perpendicular of these arcs cuts through the midpoint.
How do you get a perpendicular bisector on a line segment?
Set a compass to draw a circle with a radius that's more than half the length of the line segment but less than the whole length.Put the compass point at one end of the segment and draw an arc above the middle of the segment and another below the middle of the segment.Put the compass point at the other end of the segment and again draw arcs above and below the middle of the segment, intersecting the first two arcs.Draw a line connecting the point where the two arcs intersect above the segment and the point where they intersect below the segment.That's your perpendicular bisector.
What are the three arcs of the circle?
Circles have infinitely many arcs, not just 3.
What would be the best tool to locate the center of a circle?
The best tool to locate the center of a circle would be a compass. By placing the compass on the edge of the circle and drawing an arc, then repeating this process from another point on the circle, the intersection point of the arcs will give you the center of the circle.
Two arcs of a circle are congruent if and only if associated chords are perpendicular?
In the same circle, or in congruent circles, two minor arcs are congruent if and only if their corresponding chords are congruent.
Arcs of a circle that have exactly one point in common are called what?
Adjacent Arcs
How do you find a point which is equidistant from a given pair of points?
Bisect two arcs above and below the given points or line and the perpendicular of these arcs cuts through the midpoint.
What is the first step in the construction of a line perpendicular to AB and passing through an external point M?
Draw a straight line and with compass mark off two joined arcs above and below the line and then join the arcs together which will produce a perpendicular line.
Can there be congruent arcs on a circle?
Yes, there can be congruent arcs on a circle. Arcs which subtend the same angle at the center are considered as congruent.
Construct a circle with a radius r. mark a point on the circle. construct a tangent thourgh this point.?
1) draw the circle with a radius r and the center at O. 2) mark a point, A, on the circle 3) draw a line from O to A and beyond to point B, a little longer than the radius 4) draw a perpendicular bisector at point A using line OB 5) the perpendicular bisector is the tangent at point A In case, you forgot about drawing the perpendicular bisector. Here is the procedure: a) use your compass and mark equidistant points C and D from point A on line OB (make the length slightly less than half the radius); one point should be outside the circle and the other within. b) use your compass and draw an arc from point C and then from point D, with the arc radii being identical and about as long as the circle radius; the two arcs should intercept at two locations, E and F, one on each side of line OA. c) join points E and F to form the perpendicular bisector of line CD ===============================
How do you Draw Arcs in GstarCAD?
An arc is a portion of a circle. The default method for drawing arcs is to specify three points-the start point, a second point, and the endpoint. You can draw an arc using several different methods.
How do you get a perpendicular bisector on a line segment?
Set a compass to draw a circle with a radius that's more than half the length of the line segment but less than the whole length.Put the compass point at one end of the segment and draw an arc above the middle of the segment and another below the middle of the segment.Put the compass point at the other end of the segment and again draw arcs above and below the middle of the segment, intersecting the first two arcs.Draw a line connecting the point where the two arcs intersect above the segment and the point where they intersect below the segment.That's your perpendicular bisector.
Arcs of the same circle or congruent circles that have the same measure?
Congruent Arcs
What are the three arcs of the circle?
Circles have infinitely many arcs, not just 3.
What would be the best tool to locate the center of a circle?
The best tool to locate the center of a circle would be a compass. By placing the compass on the edge of the circle and drawing an arc, then repeating this process from another point on the circle, the intersection point of the arcs will give you the center of the circle.
How do I find the perpendicular of a line?
Using only a compass & straight edge (classic style), draw a circle around any point on the line. All you need is the two tiny arcs crossing the line. Then taking the two places where your first arcs crossed the line as centers, draw two bigger circles around those points. Note that each circle will each cross the line at two points. You actually need just the two points from each center "toward" the other center. (Don't make the two second circles so big that the radius is greater than the distance between the two points (though this will still work). This will give you two arcs across the line, and they will intersect each other above and below the line. If you then take your straight edge and draw a line through your original line from one of those intersections to the other, this new line will be perpendicular to the original line. Use the link to the Wikipedia article and look at the construction. It's actually the construction of a perpendicular through a line from a point off the original line, but check it out and note the green arcs, which would be your two second arcs from the two centers you found with your first circle. The blue line is the perpendicular to the original (the black) line. m2=-1/m1 where m1=grad of the original line & m2=grad of the line perpendicular to the original line
